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Troyanec [42]
2 years ago
6

A mass attached to a spring is pulled toward the floor so that its height above the floor is 10 mm (millimeters). The mass is th

en released and starts moving up and down reaching maximum and minimum heights of 20 and 10 mm , respectively, with a cycle of 0.8 seconds.
a) Assume that the height h(t) of the mass is a sinusoidal function, where t is the time in seconds, sketch a graph of h from t = 0 to t = 0.8 seconds. t = 0 is the time at which the mass is released.
b) Find a sinusoidal function for the height h(t).
c) For how many seconds is the height of the mass above 17 mm over one cycle?

(would anyone like to talk not to be weird or anything lol)
Mathematics
1 answer:
spin [16.1K]2 years ago
5 0
The answer would be C second height mass
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We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.

First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.

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Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.

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So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.

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The area of the triangle is 7.5 units².

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25 + 7.5 = 32.5

The area of the figure, then, is 32.5 units².

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