What do you call the inside of an atom?
2 answers:
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Question:
What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?
a. disaccharide
b. carboxylic acid
c. hemiacetal
d. ester
e. stereoisomer
Answer:
hemiacetal forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group
Explanation:
It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.
Answer:
Option-B (2-methylpropene)
Explanation:
The reaction scheme is attached below,
In first step the alkene acts a nucleophile and adds H⁺ across double bond yielding a stable tertiary carbocation.
In the second step the oxygen atom of methanol acts as nucleophile and attacks the positive charge carrying carbon atom resulting in the formation of t-butyl methyl ether.
0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.
Explanation:
Data given:
Volume of the base = 47 ml
molarity of the base= 0.39 M
volume of the acid = 25 ml
molarity of the acid =?
For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:
Macid X Vacid = Vbase x Mbase
Macid =
putting the values given in the rearranged equation above:
Macid =
= 0.73 M
The concentration of the sulphuric acid needed is 0.73 M.