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Hunter-Best [27]
3 years ago
5

Athe gas that siports burning is

Chemistry
1 answer:
kondaur [170]3 years ago
7 0
The answer is E it’s killing all oxygen that is around you
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When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same tempera
just olya [345]
<span>8.21 L of C3H8(g) Lets take c as the molar volume at that temperature.
    c L <><> 5c L
  C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
  8.21 L <><> x L
    x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.</span>
5 0
3 years ago
I Really Need Help:(
GarryVolchara [31]
Semi-conductor,brittle not malleable or ductile.
3 0
3 years ago
How many hours per year does a high school student spend in school?<br> hours per year
Liono4ka [1.6K]

Answer:

1,260 is your answer plz mark if this right

Explanation:

4 0
3 years ago
The heating curve shows the energy gain of a substance as it changes from solid to gas. Which section of the graph shows the liq
Schach [20]

Answer:

C. C

Explanation:

The heating curve is a graphical representation shows that how different phases of substances change as it is influenced by the increase in temperature or heat.

Section A represents solid phase, Section B represents solid-liquid phase, section C represents liquid phase, section D represent liquid-gas phase and section E represents gas phase.

Section C of the graph shows the liquid phase of the substance gaining kinetic energy. During Phase C, heat energy is absorbed and liquid particles gain kinetic energy to change into gas form that is section E.

Hence, the correct option is C.C.

7 0
3 years ago
One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.00 liters against a constant external pressure
Leya [2.2K]

Answer : The work done on the surroundings is, 709.1 Joules.

Explanation :

The formula used for isothermally irreversible expansion is :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done

p_{ext} = external pressure = 1.00 atm

V_1 = initial volume of gas = 1.00 L

V_2 = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(1.00atm)\times (8.00-1.00)L

w=-7L.atm=-7\times 101.3J=-709.1J

The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.

Therefore, the work done on the surroundings is, 709.1 Joules.

4 0
3 years ago
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