Answer:
The answer is that ethane gas has a density of 1.34 g/L at STP
Explanation:
Ethane weighs 0.0013562 gram per cubic centimeter or 1.3562 kilogram per cubic meter, i.e. density of ethane is equal to 1.3562 kg/m³; at 0°C (32°F or 273.15K) at standard atmospheric pressure.
Metallic I’m pretty sure. :)
Answer:
Pressure = 1.14 atm
Explanation:
Hello,
This question requires us to calculate the final pressure of the bottle after thermal equilibrium.
This is a direct application of pressure law which states that in a fixed mass of gas, the pressure of a given gas is directly proportional to its temperature, provided that volume remains constant.
Mathematically, what this implies is
P = kT k = P / T
P1 / T1 = P2 / T2 = P3 / T3 =........= Pn / Tn
P1 / T1 = P2 / T2
P1 = 1.0atm
T1 = -15°C = (-15 + 273.15)K = 258.15K
P2 = ?
T2 = 21.5°C = (21.5 + 273.15)K = 294.65K
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (1.0 × 294.65) / 258.15
P2 = 1.14atm
The pressure of the gas after attaining equilibrium is 1.14atm
Answer:
3). 1.30 × 10^(24) molecules
Explanation:
From avogadro's law which state that equal volume of all gases at the same temperature and pressure contain the same number of molecules.
We can relate it to this question as;
V₁/n₁ = V₂/n₂
Where;
V₁ is initial volume
n₁ is initial number of molecules
V₂ is final volume
n₂ is final number of molecules
Thus at STP, we have V₁ = V₂ and as such Plugging in the relevant values gives;
5/(1.30 x 10^(24)) = 5/n₂
n₂ = 1.30 x 10^(24) molecules
