Answer:
(a) r = 6.26 * 10⁻⁷cm
(b) r₂ = 6.05 * 10⁻⁷cm
Explanation:
Using the sedimentation coefficient formula;
s = M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle
s = M ( 1 - Vρ) / N*6πnr
making r sbjct of formula, r = M (1 - Vρ) / N*6πnrs
Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s
r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)
r = 6.26 * 10⁻⁷cm
b. Using the formula r₂/r₁ = s₁/s₂
s₂ = 0.035 + 1s₁ = 1.035s₁
making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁
r₂ = 6.3 * 10⁻⁷cm / 1.035
r₂ = 6.05 * 10⁻⁷cm
<h3><u>Answer;</u></h3>
Cellulose
<h3><u>Explanation</u>;</h3>
- Cellulose is a polysaccharide and the most abundant organic compound on the Earth's surface.
- <em><u>It is an important organic molecule due to its strong structure which provides a wide variety of functions. </u></em>
- <em><u>Cellulose is a major component of tough cell walls that surround plant cells and is what makes plant stems, leaves, and branches very strong.</u></em>
- The molecules of cellulose are arranged such that they are parallel to each other joined by hydrogen bond. this arrangement forms long structures that combine with other cellulose molecules producing a strong support structure.
Data Given:
Time = t = ?
Current = I = 10 A
Faradays Constant = F = 96500
Chemical equivalent = e = 107.86/1 = 107.86 g
Amount Deposited = W = 17.3 g
Solution:
According to Faraday's Law,
W = I t e / F
Solving for t,
t = W F / I e
Putting values,
t = (17.3 g × 96500) ÷ (10 A × 107.86 g)
t = 1547.79 s
t = 1.54 × 10³ s
B. light reflects off of the t shirt and enters the human eye
Answer: X3Y2
Explanation:
The formula is
X has a valency of 2
Y has a valency of 3
So, we interchange the valencies
Therefore, the formula is
X3Y2
