Question

If WS = 4.5 mm, find the length of the arc TS. Round to the nearest tenth.

Answer 1

Answer:

Solution,

<TWR = <PWQ = 128° [Vertically opposite angles]

<TWS = 128°-31° = 97° = $\frac{97\pi ^{c}}{180}$ = ∝

Arc TS (l) = ?

Radius (r) = 4.5mm

Now,

$\alpha = \frac{l}{r} \\or, \frac{97\pi ^{c}}{180} = \frac{l}{4.5} \\or, l = \frac{(97\pi)(4.5) }{180} = \frac{436.5\pi }{180}$≈ 7.61mm