y=x^2 + x - 2
x + y = 1
Replace y in the second equation:
x + x^2 + x -2 = 1
Simplify:
x^2 + 2x -2 = 1
Subtract 1 from both sides:
x^2 + 2x -3 = 0
Factor:
(x-1) (x+3) = 0
Solve for both x's:
x = 1 and x = -3
Now replace x in the second equation and solve for y using both x values:
1 + y = 1, y = 0
-3 + y = 1, y = 4
Now you have (1,0) and (-3,4) as solutions for (x,y)
XY = x times y:
1 x 0 = 0
-3 x 4 = -12
The answer would be -12
Answer:
A
Step-by-step explanation:
Hundreds - 9
Tens - 0
Ones - 4
Decimal point - .
Tenths - 1
Hundredths - 8
Hope this helped!
If you get 0 as the last value in the bottom row, then the binomial is a factor of the dividend.
Let's say the binomial is of the form (x-k) and it multiplies with some other polynomial q(x) to get p(x), so,
p(x) = (x-k)*q(x)
If you plug in x = k, then,
p(k) = (k-k)*q(k)
p(k) = 0
The input x = k leads to the output y = 0. Therefore, if (x-k) is a factor of p(x), then x = k is a root of p(x).
It turns out that the last value in the bottom row of a synthetic division table is the remainder after long division. By the remainder theorem, p(k) = r where r is the remainder after dividing p(x) by (x-k). If r = 0, then (x-k) is a factor, p(k) = 0, and x = k is a root.
