Cross multiplying we get
x^2 = 2*7x
x^2 = 14x
x^2 - 14x = 0 is the answer
4 = 7 - 3
1 = 4 - 3
-2 = 1 - 3
-5 = -2 - 3
=> An = A (n-1) - 3, where A1 = 7
The next term is A6 = A5 - 3 = - 5 - 3 = - 8
So the answer is the fourth option.
For this case we define the following variables:
x: Number of party dresses
y: Number of suits
You have 30 hours per week to cut, that is, the first equation is given by:

It is also known that 25 hours per week are available for sewing, that is:

It has a system of two equations with two unknowns, solving we have:

Multiplying the second equation by -1:

Adding up:

Substituting x in the first equation:

Clearing and:


Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.
Answer:
5 Party dresses
5 Suits