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Inessa [10]
3 years ago
15

An expression is given that has a value between 4.44.4 and 4.54.5, and where xx represents an integer. ​ ​ \sqrt{x}+\sqrt{x} x ​

+ x ​ ​ What is the value of xx?
Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

Given

\sqrt x + \sqrt x = (4.4,4.5)

Required

Find x

When the result is 4.4, we have:

\sqrt x + \sqrt x = 4.4

This gives:

2\sqrt x = 4.4

Divide both sides by 2

\sqrt x = 2.2

Square both sides

x = 2.2^2

x = 4.84

When the result is 4.5, we have:

\sqrt x + \sqrt x = 4.5

2\sqrt x = 4.5\\

Divide both sides by 2

\sqrt x = 2.25

Square both sides

x = 2.25^2

x = 5.0625

So, the value of x is between 4.84 and 5.0625

i.e.

x = (4.84,5.0625)

The only integer between the above interval is 5.

Hence:

x = 5

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Find the inverse of the function f(x) = 2x – 4.
kogti [31]

First  make x the subject of the relation:-

f(x) = 2x - 4

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Now replace x by the inverse f-1(x) and f(x) by x :-

f-1(x) =  (x + 4) / 2

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4 years ago
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Gabe has 60 coins consisting of quarters and dimes. The combined value of the coins is $9.45. Find how many quarters and dimes G
Ugo [173]
We could say that dimes = x and quarters = 60 -x

Then we use the value of the coins 

10(x) + 25(60-x) = 945

I did 945 because I am doing this in cents not dollars but the answer would still work because it is asking for the amount of coins.

10x + 1500 - 25x = 945

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3 years ago
Which equation illustrates the additive inverse property?
Minchanka [31]

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3 years ago
Rewrite the form In exponential form:<br> Log100 = x
andrey2020 [161]

Answer:

10^x=100

Step-by-step explanation:

You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that 3^2=9; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: \log_3{9}=2, which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like \log1000 uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression \log100=x means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is 10^x=100.

(If we wanted to, we could also solve this: 10^2=100, so \log100=2)

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3 years ago
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