The possible values of x for the following functions are values on real number except 0 and 1
<h3>Domain of a function</h3>
The domain of a function are the values of the independent variable for which it exists.
Given the function below
f(x)=2-x/x(x-1)
The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;
x(x -1) = 0
x = 0 and x = 1
Hence the possible values of x for the following functions are values on real number except 0 and 1
Learn more on domain of a function here; brainly.com/question/1770447
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Step-by-step explanation:
It's a proportion.
Here is your process:
15*4=60
60/20=3
3=y
:)
A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.
Let's look at your function.


is in the numerator. It is defined for every value of x. There is no problem there.

is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.
We set it equal to zero and solve the equation for x.



For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).
The answer is:
Well, there can be two answers. So, plus 3 other friends (4 people total) are sharing stickers.
To answer this, all you need to do is count by four.
4 is not greater than 7 so can not be the answer
4+4 or 8 IS greater than 7 and less than 13 so it can be the answer
4+4+4 or 12 IS ALSO GREATER THAN 7 and less than 13 so it can be the answer
4+4+4+4 is 16 and is greater than 13 so it cannot be the answer
SO it is either 8 or 12 stickers