Can any one help me on this? this is on my math test due at 11:59.

Mathematics

2 answers:

Gnesinka [82]3 years ago

7 0

Answer:

x≈17.5

Step-by-step explanation:

a^2 + b^2 = c^2 (In this case, c is x.)

Subsitute.

9^2 + 15^2 = c^2

Solve.

81 + 225 = c^2

306 = c^2

Square both sides.

√306 = √c^2

17.4928556845 = c

Round to nearest tenth.

17.5 = c

andrezito [222]3 years ago

4 0

Answer:

17.5 units

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem which states that a^2+b^2=c^2

Plug in what we know....

9^2+15^2=c^2

81+225=c^2

c=sqrt(306)

c=17.5

You might be interested in

The table shows the number of points scored each game for 2 different basketball teams. Find the mean absolute deviation(M. A. D

N76 [4]

Answer:

mean:

team 1: 41

team 2: 56

Step-by-step explanation:

add all numbers then divide by how many numbers

3 0

2 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$