Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Answer:
8 x 8 x 8 x 8 = 4096
Step-by-step explanation:
Its an exponent which means you multiply 8 by itself 4 times to get 4096.
Answer: YES
Plug in the numbers in your head.
y=3(10)+7
y=30+7
y=37 which is the y intercept
Answer:
p=22
Step-by-step explanation:
180-70-2p-3p=0
110=2p+3p
110=5p
p=110÷5
p=22
Answer:

Step-by-step explanation:
Since
due to
is an angle bisector, we have the following:
