Answer: the equation is
4x^2 + 4x - 12
Step-by-step explanation:
A quadratic equation is an equation in which the highest power of the unknown is 2.
The general form of a quadratic equation is expressed as
ax^2 + bx + c
Where
a is the leading coefficient
c is a constant
Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.
Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)
the equation becomes
(x+2)(x-1)
= x^2 - x +2x - 3
= x^2 + x - 3
Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes
4(x^2 + x - 3)
= 4x^2 + 4x - 12
<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,
The zeros of the polynomials are,
Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
6. (A/pi = r^2)
7. [(P - 2l)/2 = w]
8. [C/(2pi)= r]
9. (2A/h = b)
10. (E/c^2 = m)
