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solmaris [256]
3 years ago
8

(03.01LC) what does this mean​

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

03. Is the module, 01 is the lesson

Step-by-step explanation:

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Y= 1/2x -2 is the equation for this line.
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3 years ago
Ms. Swanson asked the question, "How does knowing the fact 6 × 5 6×5 help you find 60 × 500 60×500?" Maria answered, "I know 6 ×
Allushta [10]

Answer:

Correct answer is 30,000

Step-by-step explanation:

From multiplication :

6 * 5 = 30

Now moving to:

60 * 500

Number of ending zeros in both values = 3 ; (000)

This 3 0's will be placed at the end of the result of multiplying 6 by 5

Hence,

6 * 5 = 30

60 * 500 = 30+000 = 30,000

Hence, 60 * 500 = 30000

3 0
3 years ago
A leaf fell off a tree and floated toward the ground. What is the
pentagon [3]

Answer:

gravity

Step-by-step explanation:

the time it take to fall and force

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3 years ago
Joseph has saved $325. He wants to purchase a surfboard that costs $785. If he saves $12 each week from the money he earns mowin
Semmy [17]

Answer: 25.6 weeks

Step-by-step explanation:

He has saved $325 already so the amount left to purchase the surfboard is:

= 785 - 325

= $460

He saves $12 and $6 every week.

= $18.

Number of weeks left:

= 460/18

= 25.6 weeks

6 0
3 years ago
Please help if you can pic attatched
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

Subtract row 3 from row 1:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]

Subtract row 3 from 7 times row 2:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]

Divide row 3 by 17:

\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

Subtract 2 of row 3 from row 2:

\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

Subtract 6 of row 2 from row 1:

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]

C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]

C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]

3 0
3 years ago
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