We already know that PQ and ST are congruent because they both equal 4 and QR and TU are congruent because they both equal 6. Also I'm not sure if it is marking the two angles congruent but it looks like that to me so if that is the case then both of the triangles are congruent by SAS, PQ=ST, WR=TU, angle PQR = angle STU.
Now that we need to set up a system of equations to find y. Since we already proved the triangles congruent SU must be = to PR because of CPCTC "corresponding parts of congruent triangles are congruent" So the equation would be:
3y-2=y+4 (move y variable to one side) subtract y from right, add 2 to right
2y=6 (divide)
y=3
Then plug 3 into where y is (and since we need PQR perimeter plug it into 3(3)-2) and PR should equal 7 so add up all the sides (4+6+7) and your perimeter is 17ft.
Answer:
about 58 miles
Step-by-step explanation:
10+12+12+12+12= 58
Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
Answer:
(6,0)
Step-by-step explanation: