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Varvara68 [4.7K]
3 years ago
6

Atomic mass number of first 30 elements

Chemistry
1 answer:
dangina [55]3 years ago
4 0

Answer:

Element Atomic Number Atomic Mass

Nickel          27                          58.6934

Cobalt             28                   58.9332

Copper            29                  63.546

Zinc                   30                            65.39

Explanation:

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You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
2 years ago
8. How many grams are there in 5 moles of lithium?
nikitadnepr [17]

Answer: m = n·M = 34.7 g

Explanation:

M(Li) = 6.941 g/mol, n = 5 mol

6 0
3 years ago
Calculate the number of ATP generated from one saturated 10 ‑carbon fatty acid. Assume that each NADH molecule generates 2.5 ATP
larisa86 [58]

Answer:

Total ATP molecules produced = 66 molecules of ATP

Explanation:

A 10-carbon fatty acid when it has undergone complete oxidation will yield 5 acetyl-CoA molecules and 4 FADH₂ and 4 NADH molecules each. Each of the 5 acetyl-CoA molecules enters into the citric acid cycle and is completely oxidized to yield further ATP and  FADH₂ and NADH molecules.

The total yield of ATP in the various enzymatic step is calculated below:

Acyl-CoA dehydrodenase = 4 FADH₂

β-Hydroxyacyl-CoA dehydrogenase = 4 NADH

Isocitrate dehydrogenase = 5 NADH

α-Ketoglutarate dehydrogenase = 5 NADH

Succinyl-CoA synthase = 5 ATP (from substrate-level phosphorylation of GDP)

Succinate dehydrogenase = 5 FADH₂

Malate dehydrogenase = 5 NADH

Total ATP  from FADH₂ molecoles = 9 * 1.5 = 13.5

Total NADH molecules = 19 * 2.5 = 47.5

Total ATP molecules produced = 13.5 + 47.5 + 5

Total ATP molecules produced = 66 molecules of ATP

6 0
2 years ago
Anyone know this please and thank you
Bas_tet [7]

Answer:

The correct answer is a hypothesis.

8 0
1 year ago
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