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Lunna [17]
3 years ago
13

Assume that a watermelon dropped from a tall building falls y = 16t ^ 2 ft in t sec. Find the watermelon's average speed during

the first 6 sec of fall​
A)97 ft/sec
B)48
c)96
D 192
Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

A.) 96 ft/sec

Step-by-step explanation:

to find the average speed of the watermelon's fall in 6 seconds, substitute 6 as t in the equation and then divide by 6: y = \frac{16(6)^{2} }{6} = 96 ft/sec

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Consider the following hypothesis test:
Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

H_0: \mu\leq50\\\\H_a:\mu> 50

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0
4 years ago
2. In what ratio does the point (5, 4) divide the given line joining the points (2,1) and (7,6)​
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Answer:

3/2

Step-by-step explanation:

Let it be

C (5;4) , A (2;1) ; B(7;6)

Suppose that C divide the line AB in ratio m/n from point A (AC is m, CB is n)

Use the formula xc=(m*xb+n*xa)/ (m+n)

5=(m*7+2n)/(m+n)

5m+5n= 7m+2n

2m=3n

m/n=3/2

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3 years ago
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