The answer is B. Complete information.
A sample means only part of the whole. From the day the email was created till it was cancelled is the whole population. Consider that no mails will no longer go in because it is closed so no more additional information or data will enter that category. So it would be considered as complete. If the situation were to ask from one point to another before it was cancelled it would be considered as a sample.
Answer:
DSSD
Step-by-step explanation:
Answer:
y= -3x-20
Step-by-step explanation:
°First find the gradient between the two points
Gradient= - 3
°Using the formula y= mx+c substitute the gradient into the equation. You'll get something like this: y=-3x+c
°Substitute the point (-8;4) in the above equation. You'll get something like this : 4=-3(-8) +c
°Calculate the value of c. It'll give you c=-20
°Substitute c=-20 in the equation
Final answer is y= - 3x-20
Answer:
Step-by-step explanation:
f(x) = x2 + 2x - 2 should be rewritten using " ^ " to indicate exponentiation:
f(x) = x^2 + 2x - 2.
We find a couple of key points and use the fact that this parabola is symmetric about the line
-2
x = ----------- = -1. When x = -1, y = f(-1) = (-1)^2 + 2(-1) - 2, or 1 - 2 -2, or -3.
2(1)
Thus the vertex is at (-1, -3). The y-intercept is found by letting x = 0: y = -2. The axis of symmetry is x = -1.
Graph x = -1 and then reflect this y-intercept (0, -2) about the line x = -1, obtaining (-2, -2). If necessary, find 1 or two more points (such as the x-intercepts).
To find the roots (x-intercepts), set f(x) = x^2 + 2x - 2 = 0 and solve for x.
Completing the square, we obtain x^2 + 2x + 1 - 2 = + 1, or (x + 1)^2 = 3.
Taking the square root of both sides yields x + 1 = ±√3. One of the two roots is x = 1.732 - 1, or 0.732, so one of the two x-intercepts is (0.732, 0).
Answer:
x = 10
m<A = 132 degrees
m<B = 48 degrees
Step-by-step explanation:
Supplementary = angles that make up 180 degrees
We know <A and <B are supplemntary, so 2x+28+6x+72 = 180.
8x + 100 = 180
8x = 80
x = 10
I input 10 into the equations to solve for the measures of the angles
