The molarity of HCl is 0.95 M
Molarity can be defined as the number of moles in a volume of 1 L.
amount of HCl moles in 1000 mL - 0.95
Amount of HCl moles in 1 mL - 0.95/1000
Therefore HCl moles in 172 mL - 0.95/1000 x 172
Amount of HCl - 0.16 mol
Answer:
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
Explanation:
Using the formula
Ca Va = Cb Vb
Cb = 0.32 M
Vb = 50 mL = 50/1000 = 0.050L
Ca = 0.5 M
Va =?
Substituting for Va in the equation, we obtain:
Va = Cb Vb / Ca
Va = 0.32 * 0.05 / 0.5
Va = 0.016 / 0.5
Va = 0.032 L
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
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<span>a. gains a proton and loses a neutron. </span>This process gives more stability to the atom.
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