Because it requires more energy to create a neutron from a proton than it does to create a proton from a neutron, protons were formed more frequently than neutrons in the early universe. The correct answer is option b.
To find the answer, we need to know more about the early universe.
<h3>How the formation of proton over neutrons was favored in the early universe?</h3>
- A neutron is produced with greater energy than a proton.
- However, later on, some of the protons were changed into neutrons.
- Contrary to some claims, the proton is a stable particle that never decays, but the neutron is unstable outside of the nucleus and decays with a half life of around 10.5 minutes.
- However, very few would have had time to decay on the timeline you mention in your question.
- Every matter particle should have been accompanied by an antimatter particle, and every proton, neutron, and electron, by an anti-neutron and a positron, respectively.
- Where did all the antimatter go is the great mystery. There have been a few attempts to explain this, but they have failed.
Thus, we can conclude that, the correct answer is option b.
Learn more about the early universe here:
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There are two oxygens on the left side of the equation and three on the right
<span>The balanced chemical equation for this reaction is:
2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)
According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.
The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)
mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4
As per the equation, the number of moles of NaOH used is:
0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH
Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :
Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M
Therefore, the concentration of NaOH is 0.67 M.</span>
Electrical energy to light and heat energy
Answer: 1.31
Explanation:
No.of moles = given no.of atoms/Avagadro number
= 7.91×10^23 / 6.022 x 10^23
= 1.31
therefore, no.of moles = 1.31
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