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Ksenya-84 [330]
3 years ago
11

Please answer this I need it answered really soon thank you so much whoever answers this and I will give BRAINLIEST!!

Chemistry
2 answers:
max2010maxim [7]3 years ago
3 0

Answer:

B extinction

Explanation:

as the species does not exist any more, the species is extinct, therefore making the pictured fossil of an extinct species

hope this helps

LiRa [457]3 years ago
3 0

Answer:

B

Explanation:

As the species no longer exists, it is an example of extinction, the termination of a species.

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Convert 90.23 kPa into atm
svlad2 [7]

Answer:

The answer is

<h2>0.89 atm </h2>

Explanation:

To convert from kPa to atm we use the conversion

101.325 kPa = 1 atm

If

101.325 kPa = 1 atm

Then

90.23 kPa will be

\frac{90.23}{101.325}  \\  =0.89050086...

We have the final answer as

<h3>0.89 atm</h3>

Hope this helps you

6 0
3 years ago
In the water cycle, matter moves against the pull of gravity during
V125BC [204]
Evaporation and transpiration
5 0
3 years ago
Read 2 more answers
It is found when an unknown solid solute is dissolved in water that the solubility of the solid increases if temperature is decr
mina [271]

Answer:

exothermic entropy is increased

Explanation:

An exothermic process is one whose rate increases when the temperature is decreased. Hence if a decrease in temperature favours the dissolution of more solute at equilibrium, then the process is exothermic.

Similarly, the dissolution of a solute in a solvent increases the disorderliness (entropy) of the system because of the increase in the number of particles present. Hence once a solute in dissolved, the entropy of the system increases.

5 0
2 years ago
Explain how a scanning electron microscope (SEM) can be used in combination with an energy dispersive X-ray spectrometer (EDS) t
vfiekz [6]

Answer:

SEM provides detailed high resolution images of the sample by rastering a focussed electron beam across the surface and detecting secondary or backscattered electron signal. An Energy Dispersive X-Ray Analyzer (EDX or EDA) is also used to provide elemental identification and quantitative compositional information.

6 0
3 years ago
Calculate the heat required to melt 7.35 g of benzene at its normal melting point. Heat of fusion (benzene) = 9.92 kJ/mol Heat =
grigory [225]

Answer:

The heat required to melt 7.35 g of benzene at its normal melting point is 934.8 Joules.

The heat required to vaporize 7.35 g of benzene at its normal melting point is 2,893 Joules.

Explanation:

Mass of benzene = 7.35 g

Moles of benzene = \frac{7.35 g}{78 g/mol}=0.09423 mol

Heat fusion of benzene,\Delta H_{fus} = 9.92 kJ/mol

1) Heat required to melt 7.35 g of benzene at its normal melting point = Q

Q=\Delta H_{fus}\times 0.09423 mol

=9.92 kJ/mol\times 0.09423 mol=0.9348 kJ=934.8 J

(1 kJ = 1000 J)

2) Heat vaporization of benzene,\Delta H_{vap} = 30.7 kJ/mol

Heat required to vaporize 7.35 g of benzene at its normal melting point = Q

Q=\Delta H_{Vap}\times 0.09423 mol

=30.7 kJ/mol\times 0.09423 mol=2.893 kJ=2,993 J

(1 kJ = 1000 J)

3 0
3 years ago
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