Answer:
Explanation:
522 g
Explanation:
Your starting point here will be the balanced chemical equation for this combustion reaction
4
P
(s]
+
5
O
2(g]
→
2
P
2
O
5(s]
Notice that you have a
4
:
5
mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need
5
4
time more moles of oxygen gas.
Use phosphorus' molar mass to determine how many moles you have in that
93.0-g
sample
93.0
g
⋅
1mole P
30.974
g
=
3.0025 moles P
Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction
3.0025
moles P
⋅
5
moles O
2
4
moles P
=
3.753 moles O
2
<h2>Answer:</h2>
<em>Given data:</em>
1 kilogram = 1,000 grams
how many kilograms is 1,216 grams?
<em>Solution:</em>
1000 grams = 1 kilogram
1 gram = 1/1000 kilograms
1216 grams = 1/1000 * 1216 = 1.216 kilograms.
<em> Hence 1216 grams = 1.216 kilograms.</em>
The reaction between C2H6 and
Cl2 by addition is C2H4Cl2 or dichloroethane. It must be under the presence of
sunlight because halogen such as chlorine cannot easily react with the sigma
bond of alkane such as ethane.
find mass of oxygen by subtracting mass of phosphorus from the total mass
divide the masses by the molar mass to get moles
divide moles by the smallest amount of moles
multiply by 2 to get a nice number
P4O5
Answer:
False.
Explanation:
Activation energy ΔGₐ is only directly affected by the shape of the reaction coordinate curve, and is a function of kinetics.
Activation energy ΔGₐ is the minimum amount of energy needed to overcome the process of the reactant into the transition state, and finally the product. Reaction coordinate diagrams are purely based on potential energy of the molecules (electronic structure).
The <em>rate</em> at which the reaction will occur may change due to high temps, but not the actual ΔGₐ. To better understand, look at the Arrhenius equation. Ea (activation energy) is a constant, and is not affected by temperature changes. The rate constant k is only affected by temperature change.
