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dybincka [34]
3 years ago
15

What effect does the use of an uncalibrated thermometer have on the boiling point?

Chemistry
1 answer:
aleksandrvk [35]3 years ago
8 0
The pressure of the atmosphere Boiling point is defined as when the vapor pressure of the liquid equals to the atmospheric pressure then it starts to boil that temperature is called boiling point.
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Which of the following has the greatest mass, in grams? 1 atom of lead (Pb) 0.5 mol silver (Ag) atoms 0.3 mol gold (Au) atoms 25
Strike441 [17]

Answer : Option C) 0.3 mol of Gold.

Explanation : Amongst the options given in the question, 0.3 mol of Au is the greatest in mass in grams.

As 0.3 mol X atomic weight of Au (196.966) = 59.088 grams;

Silver has 0.5 mol X atomic weight of Ag (107.86) = 53.93 grams;

The other options are not relevant as they deal in the atomic range which has mass value very less as compared to the moles of elements.

Therefore, it is clear that Au has the greatest mass amongst the given choices.

8 0
3 years ago
Read 2 more answers
g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con
Tanzania [10]

Answer:

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

Explanation:

The equation used to calculate the constant for first order kinetics:

t_{1/2}=\frac{0.693}{k}} .....(1)

Rate law expression for first order kinetics is given by the equation:

t=\frac{2.303}{k}\log\frac{[A_o]}{[A]} ......(2)

where,  

k = rate constant

t_{1/2} =Half life of the reaction = 2.42\times 10^3 s

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 0.163 M

[A] = amount left after time t =  66.8% of [A_o]

[A]=\frac{66.8}{100}\times 0.163 M=0.108884 M

k=\frac{0.693}{2.42\times 10^3 s}

t=\frac{2.303}{\frac{0.693}{2.42\times 10^3 s}}\log\frac{0.163 M}{0.108884 M}

t = 1,409.19 s

1 minute = 60 sec

t=\frac{1,409.19 }{60} min=23.49 min

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

6 0
2 years ago
When a customer begins choking you should administer CPR.<br> True<br> False
yuradex [85]

Answer:

True

Explanation:

That's my answer :)

3 0
3 years ago
Read 2 more answers
Calculate the [OH-] and the pH of a solution with an [H+= .00083 M at 25 degrees
sesenic [268]
<h3>Answer:</h3>

1.2 × 10^-11 M

<h3>Explanation:</h3>

<u>We are given;</u>

Concentration of Hydrogen ions [H⁺] as 0.00083 M

<u>We are required to calculate the concentration of [OH⁻]</u>

We know that;

pH = - log [H⁺]

POH = -log[OH⁻]

Also, pH + pOH = 14

With the concentration of H⁺ we can calculate the pH

pH = -log 0.00083 M

    = 3.08

But; pH + pOH = 14

Therefore; pOH = 14 - pH

                           = 14 - 3.08

                          = 10.92

But, pOH = -log[OH⁻]

Therefore; [OH] = -Antilog(pOH)

Hence; [OH⁻] = Antilog -10.92

                     = 1.2 × 10^-11 M

Therefore, [OH⁻] is 1.2 × 10^-11 M

6 0
3 years ago
Is chocolate milk a pure substance or mixture
Valentin [98]
Mixture; it contains water, surgar, fat, protein, etc.
5 0
3 years ago
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