Answer:
Oxygen is the limiting reactant
Explanation:
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
2moles of hydrogen will require 1mol of oxygen to produce 2mol of water
in the question, 6.45g of O2 reacts with 1.13g of H2.
molar mass of O2 = 16*2 =32g/mol
molar mass of H2 = 1*2=2g/mol
number of moles of O2 = mass/molar mass
= 6.45/32
=0.20156moles
number of moles of H2 = 1.13/2
=0.565moles
but 0.20156moles of O2 will require 0.40312moles of hydrogen
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
0.40312mole 0.20156mol
0.40312moles is less than 0.565moles of H2 present, which means hydrogen is in excess hence implying that oxygen is the limiting reactant
Answer:
a. 300 Kg of fertilizer
b. 225 Kg of fertilizer
c. 400 Kg of fertilizer
d. 600 Kg of fertilizer
Explanation:
The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.
Therefore a 1 Kg bag contains;
40/100 * 1 Kg = 0.4 Kg of Nitrogen;
15/100 * 1 Kg = 0.15 Kg of phosphorus;
10/100 * 1 Kg = 0.1 Kg of potassium
Quantity of fertilizer required to add to a hectare to supply;
a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer
b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer
c. Phosphorus at a rate of 60 kg/ha = 60/0.15 = 400 Kg of fertilizer
d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer
Answer:
Density is defined as how tightly or loosely packed a substance is, or to the number of things or people in a certain area.
Answer:
Explanation:
=> Weight is an attractive force which is exerted on any body.
=> It changes when the object's place changes as it depends upon the acceleration due to gravity ( g = 9.8 m/s ) which changes as we move from place to place.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>
Answer:
This is a ratio of two small integers, 1.500 = 3:2. Let's assume that in the molecule of ferrous oxide there is one oxygen atom and one iron atom, and the ratio of the mass of the oxygen atom to the mass of the iron atom is 0.2865.
Explanation:
Molecular weight of Iron (II) oxide= FeO Molecular weight of Iron (III) oxide= Fe2O3
In FeO , every one iron atom contains one oxygen atom.
In Fe2O3, every one iron atom contains 1.5 oxygen atoms.
So FeO(II) will contain more Iron than FeO(III).
Calculation of percentage of iron is not necessary. I think this argument
alone is enough to prove this.
However on calculating the % of Fe, in FeO and Fe2O3 we get,
% of Iron in FeO= 55.85/(55.85+16) =55.85/71.85= 77.73%
% of Iron in Fe2O3= (2 x55.85)/(111.7+48)
=111.7/159.48 = 69.94%
