Answer:
1. Option A
2. Option B
Step-by-step explanation:
I would like to elaborate on the answer to the second question, since the first answer is actually option a. Why? The question asks for a parametric equation, not set, so it would be choice a.
2. x=3t + 5 - isolate t
t=(x-5)/3 - substitute into the second equation
y = [(x-5)/3]^2 - 1
your solution is option b
First create the equation y=Mx+ B
B is the y intercept so when y = 0, B = -1.
Now we have y=Mx - 1
The slope is M. We can calculate this by using the formula M = (y2 -y1) / (x2 - x1)
Use the points (0, -1) and (2,3) for these values. So y2 = 3, y1 = -1, x2 = 2, x1 = 0
Plug them into the equation and solve
M = (3 + 1) / (2 - 0)
M = 4/2 = 2
Now we have the equation y = 2x - 1
Next to figure out if the points given are on the line you take the values and plug them into your equation like so: 4 = 2(-2) - 1
2(-2) - 1 does not equal 4 so this point does not fall on this line. Follow this same procedure for the next point given.
