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3 years ago

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Mathematics

2 answers:

alukav5142 [94]3 years ago

7 0

Answer:

1. 3 cedis. 2. 750cedis at the end of the 3rd year.

Step-by-step explanation:

IT is p times t times r over 100

Lynna [10]3 years ago

7 0

I don’t know the answer sorry

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A ball is shot upward from a slingshot at a velocity of 15 m/s the height of the ball after t seconds is given by h(t)=10+ 5t+1/

otez555 [7]

Answer:

The instantaneous velocity after eight seconds is 9 m/s

Step-by-step explanation:

Given as :

The ball shot upward with velocity of 15 m/s

The height of the ball after t sec is given as h(t) = $10 + 5t + \frac{1}{4}t^{2}$

Now, The instantaneous velocity after 8 sec = $\frac{\partial h(t)}{\partial t}$

Or, The instantaneous velocity = $\frac{\partial (10 +5t + \frac{1}{4}t^{2})}{\partial t}$

or, The instantaneous velocity = $5 + \frac{1}{4}\times 2 t$

Now at t = 8 sec

The instantaneous velocity = 5 + 4 = 9 m/s

Hence The instantaneous velocity of ball at t = 8 sec , is 9 m/s Answer

3 0

3 years ago

PLEASE HELPPPPPPBobby took out a single loan for $500 and paid a $50 fee. His loan is due in 1 week. Find the effective interest

satela [25.4K]

Answer:

He took a loan of $500 and paid a fee of $50 on the loan. This means that #500 divided by $50 =10%

7 0

3 years ago

In the circle shown, BD is a diameter, m1 = 100° and m = 30°. m3 = _____

morpeh [17]

If a cirlce is 360* the cloest answer would have to be.... *c*

3 0

3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

Sharon jarred 18 liters of jam after 9 days. How many days does Sharon need to spend making jam if she wants to jar 20 liters of

solong [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

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