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Lelechka [254]
3 years ago
12

Use the distributive property to remove the parentheses. -8(-v(3)-3+6x(3)) The 3 in their own parenthesis are the power of 3

Mathematics
1 answer:
Ainat [17]3 years ago
6 0

Answer:

8v^3+24-48x^3

Distribute the -8 to each term to get your answer.

Hope I helped!

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The formula for the circumference of a circle is C = 2pi . Determine the circumference when the radius r is 10 cm. A. 100 approx
Archy [21]

Answer:b

Step-by-step explanation:

Circumference, C = 2pi×r

=2×pi×10

= 20pi cm

8 0
3 years ago
Solve this equation
marishachu [46]

Answer:

k=-11

Step-by-step explanation:

Rewrite the Equation.

\frac{k+3}{2} =-4

Multiply both sides of the Equation by 2.

2*\frac{k+3}{2}=2*-4

Simplify both sides of the Equation.

k+3=-8

Move all terms not containing k to the right side of the Equation.  

k=-11

5 0
3 years ago
A scale drawing of a park is 1 inch equal to 15 feet. What is the actual area of the park?
sesenic [268]

Answer:

Step-by-step explanation:

To get the current area of the park you must multiply by 15 the number of inches indicated on the map.

4 0
3 years ago
A dog is on a 5 ft leash staked to the ground. If he can rotate around the stake, forming a circle, what is the area of the gras
Zanzabum

Answer:

78.5 ft²

Step-by-step explanation:

In this situation, the dog's 5 ft leash is the radius of the circle that he forms.

So, the radius is 5.

Use the area formula, A = \pir². Plug in 5 as r, and 3.14 as \pi

A = \pir²

A = (3.14)(5²)

A = (3.14)(25)

A = 78.5

So, the area of the grass he can cover is 78.5 ft²

7 0
3 years ago
Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine
Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

7 0
3 years ago
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