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2 years ago

On a ΔABC, mΔA=80, mΔB=60 Find mΔC

Mathematics

1 answer:

Furkat [3]2 years ago

4 0

The measure of angle C (m ∠C) is 40°

<h3>Calculating angles in a triangle </h3>

From the question, we are to determine the measure of angle C (m ∠C)

In any given triangle, the sum of all the angles is 180°

Thus,

In ΔABC, the angles sum up to 180°

That is,

∠A + ∠B + ∠C = 180°

From the given information,

m ∠A = 80°, m ∠B = 60°

Thus,

80° + 60° + m ∠C = 180°

140° + m ∠C = 180°

m ∠C = 180° - 140°

m ∠C = 40°

Hence, the measure of angle C (m ∠C) is 40°

Learn more on Calculating angles in a triangle here: brainly.com/question/17738179

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The volume of a single layer in a rectangular prism is 18 cubic centimeters. There are 5 layers in this rectangular prism. What

sweet [91]

Answer: $90cm^3$

Step-by-step explanation:

A rectangular prism is a three-dimensional solid.

A rectangular prism has six faces (each one of these faces are rectangles), eight vertices and twelve edges.

You know that this rectangular prism has 5 layers and the volume of one of these layers is 18 cubic centimeters ( $18cm^3$ ).

Assuming that all these layers are equal, the volume of this rectangular prism can be calculated with:

$V_{prism}=5*V_1$

Where $V_1$ is the volume of one layer.

Substituting, you get:

$V_{prism}=(5)(18cm^3)\\\\V_{prism}=90cm^3$

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3 years ago

There are 450 students in the 9th and 10th grade taking geometry, and 1/3 of them are 9th graders

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There are 150 9th graders and 300 10th graders

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What is the ratio for 12:75

adoni [48]

It would be: 12/75 = 4/25

So, your answer is 4/25

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3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

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