Help. look at the screenshot below.

frutty [35]

Pt 1 - how much the value goes down each year
Pt 2 - how much the car was originally worth

3 0

2 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

2 years ago

PLEASE HELP ME PLEASE PLEASE I NEED YOUR HELP PLEASE HELP ME Which of these expressions demonstrates the identity property? Chec

Delicious77 [7]

Answer:

1st one and the third one

Step-by-step explanation:

25(0)=25

25+0=25

3 0

2 years ago

Read 2 more answers

Write an inequality that represents the situation. Jon can do less than 25 sit-ups on an exercise ball. How many sit-ups might J

o-na [289]

The inequality is x<25, when Jon cam do less than 25 sit-ups on an exercise ball.

Given that,

Jon can do less than 25 sit-ups on an exercise ball.

We have to find an inequity to illustrate the circumstance.

Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

The inequality is

Take the exercise balls as x

x<25

Therefore, the inequality is x<25, when Jon cam do less than 25 sit-ups on an exercise ball.

To learn more about inequality visit: brainly.com/question/28823603

#SPJ9

5 0

1 year ago

Someone help me please?

jeka57 [31]

The Answer

LCD = 12

Equivalent Fractions with the LCD

2/3 = 8/12

3/4 = 9/12

1/2 = 6/12

Solution:

Rewriting input as fractions if necessary:

2/3, 3/4, 1/2

For the denominators (3, 4, 2) the least common multiple (LCM) is 12.

LCM(3, 4, 2)

Therefore, the least common denominator (LCD) is 12.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

2/3 = 2/3 × 4/4 = 8/12

3/4 = 3/4 × 3/3 = 9/12

1/2 = 1/2 × 6/6 = 6/12

Hope This Was Helpful :D

6 0

2 years ago