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madam [21]
2 years ago
11

Help please (inequalities)

Mathematics
2 answers:
Liula [17]2 years ago
7 0
The first one is the correct answer hope this helps have a nice day let me know if it works
zaharov [31]2 years ago
4 0

Answer:

The First one is the answer

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X+y=5 <br> 3x-4y=8 <br> please i need the steps
grandymaker [24]

Answer:

x + y = 5

<u>3x - 4y = 8</u><u> </u><u> </u><u> </u>

3x + 3y = 15

<u>3x - 4y = 8 </u>-

7y = 7

y = 1

x + y = 5

x + 1 = 5

x = 4

x = 4

y = 1

Hope it helps!

6 0
2 years ago
Find the number of permutations in the word CIRCUS.
DerKrebs [107]
If the letters are considered distinct, then the number of permutations is 6!=720.

If we count either C as the same character, then we would be double-counting - to correct this, we would simply divided by the number of ways we can choose C from the available characters, or \dfrac{6!}{2!}=360.
8 0
3 years ago
Someone help me with this pls
Mumz [18]

Answer:

There will be approx 283908 hits.

Step-by-step explanation:

A website had 342,000 hits in 2011.

This is a decline of 2.3% from the previous year.

Decline rate = 2.3% or 0.023

So, increase rate will be 1-.023=0.977

Time = 2019-2011=8

We can calculate the answer as:

342000\times(0.977)^{8}

= 342000\times0.83014

= 283907.88 rounding to 283908.

Therefore, there will be approx 283908 hits.

4 0
3 years ago
In AABC, mZA = 32°, mZB = 25°, and a = 18. Find c to the nearest tenth.
Lena [83]

Answer:

Step-by-step explanation:

4 0
3 years ago
You could win a giant jar of M&amp;Ms, if only you could guess how many are in the jar. You find a smallerjar such that the gian
sleet_krkn [62]

Answer:

There are 7360 M&Ms in larger jar.

Step-by-step explanation:

We are given the following in the question:

A giant jar is such that it is exactly four times times the smaller jar in dimensions.

If r and h is the radius and height of the cylindrical jar respectively, then the dimensions of the larger are:

R = 4r\\H=4h

Number of M&Ms in smaller jar = 115

Volume of smaller jar =

v = \dfrac{1}{3}\pi r^2 h

Volume of larger jar =

V =\dfrac{1}{3}\pi R^2 H=\dfrac{64}{3}\pi r^2 h

Number of M&Ms in larger jar:

v = \dfrac{1}{3}\pi r^2 h\rightarrow 115\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 115\times 64\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 7360

Thus, there are 7360 M&Ms in larger jar.

6 0
3 years ago
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