3 years ago

Help please (inequalities)

Mathematics

2 answers:

Liula [17]3 years ago

7 0

The first one is the correct answer hope this helps have a nice day let me know if it works

zaharov [31]3 years ago

4 0

Answer:

The First one is the answer

You might be interested in

Help me answer this question please

Stella [2.4K]

ANSWER

${f}^{ - 1} =\pm \sqrt{x + 1}$

EXPLANATION

The given function is

$f(x) = {x}^{2} - 1$

Let

$y = {x}^{2} - 1$

Interchange x and y to get:

$x= {y}^{2} - 1$

Solve for y,

$x + 1 = {y}^{2}$

Take square root of both sides to get,

$\pm \sqrt{x + 1} = y$

This is the same as:

$y = \pm \sqrt{x + 1}$

Therefore the inverse is

${f}^{ - 1} =\pm \sqrt{x + 1}$

3 0

3 years ago

Can you use the product of powers property to simplify? ANSWER ASAP PLEASE!!!!

slavikrds [6]

Ye, np.

5^2 * 6^4= 25*1296=32400

3 0

3 years ago

What's the answer? Idk it bc I'm stupid and I don't feel like doing it

aliya0001 [1]

H=-16x to the second power +136

4 0

3 years ago

Part A; Part B; Part C;

pychu [463]

15 16 and then 17 to be an equilateral

8 0

3 years ago

Find the approximate value of the circumference of a circle with the given radius. Use pi = 3.14. Round your results to one more

svetlana [45]

C = 2πr
C = 2 * 3.14 * 5.1
C = 32.028

You can round that to A. 32.03, because if the decimal after 2 is greater than it, then you round it to the number which is higher than it, which is 3.

4 0

3 years ago

Read 2 more answers