The temperature in Canada at 6 am on Christmas was -5°C. By noon the temperature had risen by 11°C.Calculate the temperature in
Canada at noon on Christmas. *
1 answer:
Answer: 
Step-by-step explanation:
Given
The temperature in Canada at 6 am on Christmas was 
By noon the temperature had risen by 
So, the temperature in Canada at noon is

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0.24
Step-by-step explanation:
Answer:
1,250 lbs
Step-by-step explanation:
There are 2,000 in 1 ton, so 5 * 2,000 = 10,000 lbs weight limit for the bridge.
10,000-8750 = 1,250 lbs can be added to the truck before they reach the bridge weight limit.
Answer:
sinθ = y/r sinθ = 
cosθ = x/r cosθ = 
tanθ = y/x tanθ = 
cscθ = r/y cscθ = 
secθ = r/x secθ = 
cotθ = x/y cotθ =
explanation:
r = 
r = 10
x = 8
y = -6
r = 
r = 5
x = 4
y = 3
Answer:
I would say B
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
f(x) = √(x) + 12
g(x) = 2√(x)
(f-g)(x) = √(x) + 12 - 2√(x)
(f-g)(x) = 12 - √(x)
if x = 144
(f-g)(144) = 12 - √(144) = 12 - 12 = 0