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3 years ago

Whats 6278 divided by 73 long division please show the work

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

5 0

6278/73 = 86
I can't really show work in the computer so sorry at least u got the answer hope this helps.

FrozenT [24]3 years ago

4 0

I can't show the work, but if the problem is printed or on the computer, I recommend using Photomath in the AppStore :)

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if you’re good with set theory in math 30 please help with questions 31 and 32!! real answers only !!

GREYUIT [131]

Answer: 31) d 32) c

Step-by-step explanation:

31)

A = {1, 3, 5, 15}

B = {2, 3, 5, 7}

A ∪ B = {1, 2, 3, 5, 7, 15}

C = {2, 4, 6, 8}

(A ∪ B) ∩ C = {1, 2, 3, 5, 7, 15} ∩ {2, 4, 6, 8} = {2}

2 is the only number in both sets

32)

The pattern is: reflection, add symbol, ..., reflection, add symbol.

The last image shown is: add symbol

So the next image will be: reflection (flipped to the left)

7 0

3 years ago

What is the derivative of the following function? f(x) = 4x^6/cos^5(x)

KIM [24]

Answer:

$f'(x) = \frac{24x^{5} \cos x + 20x^{6}\sin x}{\cos^{6}x }$

Step-by-step explanation:

We have to find the derivative of the following function:

$f(x) = \frac{4x^{6} }{\cos^{5} x }$

Now, differentiating both sides with respect to x we get,

$f'(x) = \frac{\cos^{5}x (24x^{5}) - 4x^{6}(5\cos^{4}x )(- \sin x)}{(\cos^{5}x )^{2}}$

⇒ $f'(x) = \frac{ 24x^{5} \cos x + 20 x^{6}\sin x}{\cos^{6}x }$ (Answer)

{Since, we know that, $\frac{d(mx^{n} )}{dx} = m \times n x^{(n - 1)}$ and $\frac{d(\cos^{n} x)}{dx} = n \cos^{(n - 1)} x(- \sin x)$ }

5 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago

Plz answer quickly !!!!

SVETLANKA909090 [29]

Im pretty sure: 18 units

8 0

3 years ago

Decimals between 10 and 15 with an interval of 0.75

IgorC [24]

10.75
11.50
11.80
12.55
13.30
14.05
14.80
15.55

3 0

3 years ago