Answer:
(a) 7 essays and 29 multiple questions
(b) Your friend is incorrect
Step-by-step explanation:
Represent multiple choice with M and essay with E.
So:
--- Number of questions
--- Points
Solving (a): Number of question of each type.
Make E the subject of formula in 

Substitute 36 - M for E in 


Collect Like Terms


Divide both sides by -4


Substitute 29 for M in 


Solving (b): Can the multiple questions worth 4 points each?
It is not possible.
See explanation.
If multiple question worth 4 points each, then
would be:

Where x represents the number of points for essay questions.
Substitute 7 for E and 29 for M.


Subtract 116 from both sides



Make x the subject

Since the essay question can not have worth negative points.
Then, it is impossible to have the multiple questions worth 4 points
<em>Your friend is incorrect.</em>
Answer:
Step-by-step explanation:
Correct question
How many cubes with side lengths of ¼cm needed to fill the prism of volume 4 cubic units?
We know that,
Volume of a cube is s³
V = s³
Where 's' is length of side of a cube
Given that
The cube has a length of ¼cm, and a cube has equal length
s= ¼cm
Then, it's volume is
V = s³
V = (¼)³ = ¼ × ¼ × ¼
V = 1 / 64 cubic unit
V = 0.015625 cubic unit
Then, given that the volume of the prism to be filled is 4 cubic unit
Then,
As, we have to find the number if cubes so we will divide volume of prism by volume of one cube
Then,
n = Volume of prism / Volume of cube
n = 4 / 0.015625
n = 256
So, then required cubes to filled the prism is 256 cubes.
Answer:
Explanation:
Number the sides of the decagon: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10, from top (currently red) clockwise.
- The side number one can be colored of five different colors (red, orange, blue, green, or yellow): 5
- The side number two can be colored with four different colors: 4
- The side number three can be colored with three different colors: 3
- The side number four can be colored with two different colors: 2
- The side number five can be colored with the only color left: 1
- Each of the sides six through ten can be colored with one color, the same as its opposite side: 1
Thus, by the multiplication or fundamental principle of counting, the number of different ways to color the decagon will be:
- 5 × 4 × 3 × 2 ×1 × 1 × 1 × 1 × 1 × 1 = 120.
Notice that numbering the sides starting from other than the top side is a rotation of the decagon, which would lead to identical coloring decagons, not adding a new way to the number of ways to color the sides of the figure.
Answer:
32
Step-by-step explanation: