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Snezhnost [94]
3 years ago
5

5TH GRADE MATH HELP!!!!!!solve 757 ÷10⁴​ =

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:0.0757

Step-by-step explanation:

10^4 equals to 10*10*10*10=10000

now 757/10000=0.0757

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The general term of an arithmetic sequence is tn = 32 + 3n, where n ∈N and n ≥ 1. The sequence is A) 32, 35, 38, 41, 44, 47,...
den301095 [7]

Answer:

35,38,41,44,47,50,....

Step-by-step explanation:

n ∈N means that n is an element of Natural numbers

Natural numbers are whole non-negative numbers

n ≥ 1, means that n = 1, 2, 3, 4, 5, 6,........

tn = 32 + 3n

the first term t1 = 32 + 3(1)

                            32 + 3 = 35

the second term t2 = 32 + 3(2)

                                   32 + 6 = 38

the third term t3 = 32 + 3(3)

                              32 + 9 = 41

5 0
3 years ago
Im giving free brainlest only if you give it to me
Paraphin [41]

Answer: betttttttttttttttttttttttttttt

6 0
3 years ago
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A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
Anastasy [175]

Answer: 19.4

Step-by-step explanation:

Given

Profit is given in terms of the selling price

y=-5x^2+194x-900

to get the maximum price, differentiate y w.r.t x

\frac{\mathrm{d} y}{\mathrm{d} x}=-5\times 2x+194

Put  \frac{\mathrm{d} y}{\mathrm{d} x}=0 to get maximum value

10x=194\\x=19.4

Thus, the company must sell it at 19.4

8 0
2 years ago
1. Are these two lines parallel, perpendicular or neither?
kolezko [41]

Answer:

parallel

Step-by-step explanation:

they have the same slope, but different y intercepts

8 0
2 years ago
Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]
madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

3 0
2 years ago
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