The answer is 1/12.
The perimeter of a square garden with side s is:
P = 4s
s = 1/4P
Since it is painted 1/3 of 1/4 of the fence, the<span> fraction of the painted fence is:
1/3 * 1/4 = 1/12</span>
Find the stationary points.
<em>f(x)</em> = <em>x</em> + 16/<em>x</em>
<em>f '(x)</em> = 1 - 16/<em>x</em> ²
Solve <em>f</em> <em>'(x)</em> = 0.
1 - 16/<em>x</em> ² = 0 → <em>x</em> ² = 16 → (<em>x</em> - 4) (<em>x</em> + 4) = 0
→ <em>x</em> = -4, <em>x</em> = 4
Check the value of <em>f</em> at the stationary points. <em>x</em> = -4 is not in the provided domain so we can omit it.
<em>f</em> (4) = 8
Check the value of <em>f</em> at the boundary of the domain.
<em>f</em> (0.2) = 401/5 = 80.2
<em>f</em> (16) = 17
Then over [0.2, 16], we have max(<em>f</em> ) = 401/5 and min(<em>f</em> ) = 8.
Answer:
(x,y) (1,3)
Step-by-step explanation:
3x=-x+4
+x +x
4x=4
*divide/simply*
x=1
y=3(1)
y=3✓
y=-1+4
y=3 ✓
Assuming we're solving for x, all that needs to be done is to add 5 on both sides.
x - 5 >= -2
+5 +5
x >= 3