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stellarik [79]
3 years ago
7

Find AB.??????????????????

Mathematics
2 answers:
nexus9112 [7]3 years ago
4 0

Answer:

AB = AC

so AB is Also 3.2

.............................

Anni [7]3 years ago
4 0

Answer:

3.2

Step-by-step explanation:

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Outcome Payout HHH $10 HHT $3 HTH $0 HTT -$3 TTT $10 THH -$3 THT $0 TTH $0 Kara is playing a game where she flips a coin 3 times
TEA [102]
<span>Expected value is the sum of the probability of each even times the outcome of the event.

So she wins $10 with probability 2/8, $3 with probability 1/8, $0 with probability 3/8, and loses $3 with probability 2/8.

So,

E = 10(2/8) + 3(1/8) + 0(3/8) - 3(2/8)
=5/4 + 3/8 - 3/4
=7/4

<span>= $1.75
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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7 0
3 years ago
Rewrite 6/5 as a mixed number.​
raketka [301]

Answer:

1 1/5

Step-by-step explanation:

You see how many times the bottom number will go into the top, then the "leftovers" is your top number. 6-5=1

5 0
3 years ago
What is the answer for this equation 4/7w=24?
docker41 [41]
W=1/42 hope this helps! XD
7 0
3 years ago
Read 2 more answers
Can u guys plz give me the answer to number 1-3
jek_recluse [69]
I'm pretty sure it is 5:55


8 0
2 years ago
In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
STALIN [3.7K]

Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

10a1 = 30

a1 = 3

for f = -2

a1×-2 + a1×(-2)³ = 30

-10a1 = 30

a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

4 0
2 years ago
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