What is the point slope equation for the point (2, 5) and slope 2/3?
1 answer:
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Answer:
The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.
Approximation at points (1.1,1.9) is 0.7
Step-by-step explanation:
Given:
Tangent plane to a surface z=5x+2y-10 as the function at point (1,2)
To find :
f(x,y) at (1,2)
partial derivatives of function w.r.t. (x and y) and value of that function at given points.
Solution:(refer the attachment also)
Now we know that
the equation of tangent plane at given points to the surface is given by,
f(x1,y1,z1) and z=f(x,y)
z-z1=Fx(x1,y1)*(x-x1)+Fy(x1,y1)*(y-y1)
here Fx(x1,y1) and Fy(x1,y1) are the partial derivatives of x and y.
now
taking partial derivative w.r.t. x we get
Fx(x1`,y1)=
=5.
Then w.r.t y we get
Fy(x1,y1)=
=2.
The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.
Using the Linearization or linear approximation we get
L(x,y)=f(x1,y1)+Fx(x,y)*(x-x1)+Fy(x,y)(y-y1)
=-1+5(x-1)+2(y-2)
=5x+2y-10
Approximation at F(1.1,1.9)
=5(1.1)+2(1.9)-10
=5.5+3.8-10
=0.7
Approximation at points (1.1,1.9) is 0.7
Answer:
(a) and (b) are correct
Step-by-step explanation:
Given
See attachment for complete question
Required
Select the correct options
A clock is divided into two equal parts.
(1) 1 - 6
(2) 7 - 12
<em>When the hour hand is on (1), then the time is "after"</em>
<em>When the hour hand is on (2), then the time is "before"</em>
<em />
From the attached clock, we have:
(1) The hour hand on 9
(2) The minute hand 1 unit above 9 i.e. 46 minutes
(1) implies that, the time is before 9 i.e. past 8
(2) implies that the minutes is (60 - 46) before 9 or 46 minutes after 8
In (1) and (2) above, we have two interpretations.
1: (60 - 46) minutes before 9
This gives:
14 minutes before 9
2: 46 minutes past 8
i.e. 8 : 46
