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matrenka [14]
4 years ago
15

List the major objectives Ethiopian foreigh policy.​

Physics
1 answer:
jeka944 years ago
4 0

Answer:

no

Explanation:

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For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C

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A box of weight 20N rests on a horizontal floor. A maximum horizontal force of 6N is required to move the box along the floor .I
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10 POINTS!!! Determine the pressure of your book in pascals (Pa). Show your work! (the pressure of the book in psi is 0.03 psi)
Musya8 [376]

You've listed a lot of data here, in both metric and customary units,
and I'm not even sure it's all needed.  Let me try and boil it down:

Pressure on a surface =
               (total force on a surface)
divided by (area of the surface).

The answer to the question is the pressure expressed in pascals. 
There's actually enough information here to answer the question
in 2 different ways.  We could ...

-- simply convert (0.03 pound per inch²) to pascals, or
-- go through the whole calculation of force, area, and then their quotient. 

To me, converting 0.03 psi to Pa looks easier.

-- 1 pascal = 1 newton / 1 meter²

-- On Earth, 1 kilogram of mass weighs 9.8 Newtons and 2.2 pounds.
From this, we can calculate that

                    2.2 pounds of force = 9.8 newtons of force.

                     1 pound = 4.45 newtons

(0.03 pound/inch²) x (4.45 newton/pound) x (1inch/2.54cm)² x (100cm/1m)² =

 (0.03 x 4.45 x 1² x 100²) / (2.54² x 1²)    newton/meter²  =  206.9 Pa .

7 0
4 years ago
A 15.7 kg block is dragged over a rough, horizontal surface by a constant force of 83.1 N
Kay [80]

Answer:

The work done by the 83.1 N force is 4687.5 J.

The magnitude of the work done by the  force of friction is 1187.5 J.

Explanation:

Given:

Mass of the block, m=15.7 kg

Force acting on it, F=83.1 N

Angle of application of force, \theta = 25.7°

Displacement of the block, d=62.6 m

Coefficient of friction, \mu =0.161

Acceleration due to gravity, g=9.8 m/s²

Work done by a force is given as:

Work,W=F\times d\times \cos\theta

So, work done by the constant force is given as:

W_{force}=83.1\times 62.6\times \cos(25.7)\\W_{force}=4687.5\textrm{ J}

Now, in order to find work done by friction, we need to evaluate friction.

For the vertical direction, the net force is zero as there is no vertical motion.

Therefore,

N + F\sin\theta = mg\\ N = mg-F\sin\theta

Frictional force is given as:

f=\mu N=\mu (mg-F \sin \theta)=0.161\times ((15.7\times 9.8)-(83.1\times \sin(25.7))=18.97\textrm{ N}

Now, friction acts in the direction opposite to the displacement. Thus, angle between frictional force and displacement is 180°.

Therefore, work done by friction is:

W_{fric}=f\times d\times \cos\theta_f\\W_{fric}=12.72\times 62.6\times \cos(-180)\\W_{fric}=18.97\times 62.6\times -1\\W_{fric}=-1187.5\textrm{ J}

Negative sign indicates that frictional force is acting opposite to motion.

So, the magnitude of the work done by the  force of friction is 1187.5 J.

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A solar oven can be created by focusing the sun's rays to a point using a _________ mirror.
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Concave mirror...as it focus the light at a given point..... concave mirror is converging !!!
7 0
3 years ago
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