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2 years ago

7. A 400 kg cannon fires an 80 kg student at +15 m/s. At what velocity will

Physics

1 answer:

telo118 [61]2 years ago

6 0

Answer:

Explanation:

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3 years ago

1. What were the 3 basic concepts of government that the English brought with them to North America?

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the 3 basic concepts of government that the English brought with them to North America are listed in the answer

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3 years ago

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3 years ago

Read 2 more answers

Earth is 149.6 million meters from the Sun and takes 365 days to make one complete revolution around the Sun. Mars is 227.9 mill

luda_lava [24]

Answer:

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

Explanation:

The distance of Earth from the Sun is $149.6\times 10^{9}\,m$ and of Mars from the Sun is $227.9\times 10^{9}\,m$ . Let assume that both planets have circular orbits. The centripetal accelaration can be found by using the following expression:

$a_{r} = \frac{v^{2}}{R}$

Since planet has translation at constant speed, this formula is applied to compute corresponding speeds:

$v=\frac{2\pi\cdot r}{\Delta t}$

Earth:

$v_{earth} = \frac{2\pi\cdot (149.6\times 10^{9}\,m)}{(365\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{earth}=29806.079\,\frac{m}{s}$

Mars:

$v_{mars} = \frac{2\pi\cdot (227.9\times 10^{9}\,m)}{(687\,days)\cdot(\frac{24\,hours}{1\,day} )\cdot(\frac{3600\,s}{1\,h} )}$

$v_{mars}=24124.244\,\frac{m}{s}$

Now, centripetal accelarations can be found:

Earth:

$a_{r,earth} = \frac{(29806.079\,\frac{m}{s} )^{2}}{149.6\times 10^{9}\,m}$

$a_{r,earth} = 5.939\times 10^{-3}\,\frac{m}{s^{2}}$

Mars:

$a_{r,mars} = \frac{(24124.244\,\frac{m}{s} )^{2}}{227.9\times 10^{9}\,m}$

$a_{r,mars} = 2.554\times 10^{-3}\,\frac{m}{s^{2}}$

The ratio of Earth's centripetal acceleration to Mars's centripetal acceleration is:

$\frac{a_{r,earth}}{a_{r,mars}} = \frac{5.939}{2.554}$

$\frac{a_{r,earth}}{a_{r,mars}} = 2.325$

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3 years ago