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Nastasia [14]
2 years ago
7

A. A piece of paper near a magnet

Physics
2 answers:
irinina [24]2 years ago
6 0

Answer:

it’s c not d

Explanation:

took the test

raketka [301]2 years ago
5 0

Answer:

D

Explanation:

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5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t
Volgvan

Answer:

When primary coil is exited by sin wave,this will result in sin wave in secondary coil as well.According to law,flux induced in the secondary coil will have same waveform as in the primary coil.

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3 years ago
How do particles move when a transverse wave passes through a medium?
bagirrra123 [75]
<span> In </span>transverse waves<span>, </span>particles<span> of the</span>medium<span> vibrate </span>to<span> and from in a direction perpendicular </span>to<span> the direction of energy transport. </span>
4 0
3 years ago
The image shows mountains in Alaska.
zalisa [80]

Answer:

A syncline is visible.

Explanation:

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8 0
2 years ago
Read 2 more answers
A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done
Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

W = F*d

<em>Where</em>:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

F = W_{x} = mgsin(\theta)

<em>Where:</em>

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²    

θ: is the degree angle to the horizontal = 30°        

F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N    

Now, we can find the work:

W = F*d = 24.53 N*20 m = 490.6 J      

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0
2 years ago
Calculate the electric potential energy in a capacitor that stores 4.0 10-10 C of charge at 250.0 V
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Q = C.v
v = Q/C
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 = 4 × 10^(-10)/2.5 × 10^2
 = 1.6 × 10^(-12) volt
7 0
3 years ago
Read 2 more answers
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