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Nastasia [14]
3 years ago
7

A. A piece of paper near a magnet

Physics
2 answers:
irinina [24]3 years ago
6 0

Answer:

it’s c not d

Explanation:

took the test

raketka [301]3 years ago
5 0

Answer:

D

Explanation:

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Some drops a ball off of the top of a 125-m-tall building. In this prob-lem, you will be solving for the time it takes the ball
Nimfa-mama [501]

Answer:

t = 5.05 s

Explanation:

This is a kinetic problem.

a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m

b) in this system the equations of motion are

              y = v₀ t + ½ g t²

where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth

e)    y = 0 + ½ g t²

     t = √ (2y / g)

     t = √(2 125 / 9.8)

     t = 5.05 s

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3 years ago
Two tuning forks are played at the same time. One has a frequency of 490 Hz and the other is 488 Hz. How many beats per second a
Gnoma [55]
Hope this helps you.

7 0
3 years ago
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Electric Circuits Homework
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3 0
2 years ago
Which property help to explain differences in the specific heat capabilities of two substances
OLga [1]

Answer:

Forces between molecules

Explanation:

The tensions between molecules are the characteristic that explains variances in the specific heat capacity of two substances.

This means that a substance's specific heat capacity will increase or be higher the closer its atoms are bound together. As a result, it differs for the different states of matter, such as solid, liquid, and gas.

3 0
2 years ago
Two positive charges are labeled q Subscript 1 baseline and q Subscript 2 baseline are 0.1 m apart. Two positively charged parti
Snowcat [4.5K]

Answer:

Explanation:

Let that point be at a distance x from q1

Then Kq1/x^2= Kq2/ (s-x)^2

Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]

Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result's that's it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.

4 0
3 years ago
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