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lianna [129]
3 years ago
6

in an isolated system bicyclist 1 and bicyclist 2 each with a mass of 80 kg, collide. bicyclist 1 was moving to the right at 8 m

/s, while bicyclist 2 was moving to the left at 2 m/s. what is the magnitude of their combined momentum before the crash
Physics
1 answer:
Reika [66]3 years ago
3 0
Consider speed of bicyclist 1 as V1=+8m/s and bicyclist 2 as V2=-2m/s  m=80kg 

Since momentum has opposite signs moving to right or left   

Therefore the combined momentum , P is given by :   

P=m*V1+m*V2 =80*(8-2)kg*m/s=+480 kg m/s
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The specific heat of acetic acid is 2.07 J/gºC. If 1150 J of heat is
Doss [256]

Answer:

12.3 °C

Explanation:

Q=m*Cp*ΔT-->

1150=45*2.07*ΔT-->

ΔT=1150/93.15-->

ΔΤ=12.3 °C

4 0
3 years ago
Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,
Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0
3 years ago
what is the displacement for a driver who travels 10 km to get to a point that is 4 km from his starting point​
Cloud [144]

Answer:

4km

Explanation:

displacement is how far something has moved from its starting point

8 0
3 years ago
A truck with a mass of 1330 kg and moving with a speed of 15.0 m/s rear-ends a 805 kg car stopped at an intersection. The collis
Dovator [93]

Answer:

The Speed of the vehicles is 9.34m/s

Explanation:

For an elastic collision the two bodies move with similar velocities after collision

Given

M1=1330kg

V1=15m/s

M2=805kg

V2=0(the car is parked on neutral)

The formula is

M1V1+M2V2=(M1+M2)V

1330*15+805*0=(1330+805)V

19950+0=2135V

2135V=19950

divide both sides by 2135

V=19950/2135

V=9.34m/s

8 0
3 years ago
The natural process where the sun's energy is trapped by the atmosphere to make the Earth warm enough for life is known as
Citrus2011 [14]
I think something like radiation
8 0
4 years ago
Read 2 more answers
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