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3 years ago

10

How do I do this ???!

1 answer:

Reptile [31]3 years ago

8 0

Answer:

The answer is 24

Step-by-step explanation:

The top one is basicly 36÷3 and that = 12

The second one is 12+? So you have to find out what (?) is. You do this by doing 28-12=16 16÷2=8

The next one is 8-?=4 so what we do it 8-4=4

The final one is all the answers added together so 12+8+4= 24 -(sorry for any spelling mistakes)

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A shirt originally cost $42.54, but it is on sale for $29.78. What is the percentage decrease of the price of the shirt? If nece

Genrish500 [490]

Answer:

The difference is 30%

Step-by-step explanation:

To find the percent decrease, start by finding the difference in costs.

42.54 - 29.78 = 12.76

Now divide that amount by the original cost.

12.76/42.54 = 30%

4 0

3 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

I will give brainliest and A LOT OF POINTS please help!!!!!!!!!!!!!!!!!

DedPeter [7]

Answer:

(10,2)(20,4)(30,6)(40,8)

Step-by-step explanation:

In each bracket the first digit divided by the second is equal to 5

10÷2=5

20÷4=5

30÷6=5

40÷8=5

3 0

2 years ago

F(x)=6x^2 +10x−1

KATRIN_1 [288]

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

$D=b^2-4ac$

In this case you have the following Quadractic function provided in the exercise:

$f(x)=6x^2 +10x-1$

Let's make it equal to 0:

$0=6x^2 +10x-1$

You can identify that:

$a=6\\\\b=10$

Knowing these values, you can substitute them into the formula and then evaluate:

$D=10^2-4(6)(-1)\\\\D=124$

Therefore, since:

$D>0$

You can determine that the it has two distinct real roots.

3 0

4 years ago

If the line you graph is exactly the same as the first one, how many solutions do you

Aleks04 [339]

I think it’s infinitely many

5 0

3 years ago