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yuradex [85]
3 years ago
10

How do I do this ???!

Mathematics
1 answer:
Reptile [31]3 years ago
8 0

Answer:

The answer is 24

Step-by-step explanation:

The top one is basicly 36÷3 and that = 12

The second one is 12+? So you have to find out what (?) is. You do this by doing 28-12=16 16÷2=8

The next one is 8-?=4 so what we do it 8-4=4

The final one is all the answers added together so 12+8+4= 24 -(sorry for any spelling mistakes)

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56 points for whoever answers correctly !
vladimir2022 [97]

We need to use what we know about rectangles to get:

1)

  • Total length = 2*W + 8ft
  • Total width = W + 8ft

2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

  • Total length = L + 2*4ft = 2*W + 8ft
  • Total width = W + 2*4ft = W + 8ft

2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

area = (total length)*(total width)

area = (2*W + 8ft)*(W + 8ft) = 2*W^2 + 3*W*8ft + 64ft^2

area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

6 0
3 years ago
Anyone mind helping me solve this inequality? Step by step
dlinn [17]

By decomposing the figure in simpler shapes, we will see that the total area is:

a = 180 cm²

<h3>How to find the area of the composite figure?</h3>

Remember that the area of a rectangle of width W and length L is:

A = L*W

And the area of a triangle with base B and height H is:

A = B*H/2.

Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.

So the area of that part is:

A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²

Now, the bottom triangle has a base of 12 cm, and a height of:

15cm - 6cm = 9cm

Then its area is:

A' = 12cm*9cm/2 = 54cm²

This means that the total area of the figure is:

total area = 54cm² + 54cm² = 108cm²

If you want to learn more about area:

brainly.com/question/24487155

#SPJ1

5 0
2 years ago
Simplify this expression: 4(x+3)+3(5-x)
prisoha [69]

Answer:

x+27

Step-by-step explanation:

Let's simplify step-by-step.

4(x+3)+3(5−x)

Distribute:

=(4)(x)+(4)(3)+(3)(5)+(3)(−x)

=4x+12+15+−3x

Combine Like Terms:

=4x+12+15+−3x

=(4x+−3x)+(12+15)

=x+27

Hope you find this Useful!

8 0
2 years ago
Read 2 more answers
If a/\2+1/a/\2=11, then a+1/a=?
Nadya [2.5K]

Answer:

\pm \sqrt{13}

Step-by-step explanation:

\bigg(a +  \frac{1}{a}  \bigg)^{2} =  {a}^{2}   +  \frac{1}{ {a}^{2} }  + 2 \times a \times  \frac{1}{a}  \\  \\ \bigg(a +  \frac{1}{a}  \bigg)^{2} = 11 + 2 \\  \\   \bigg(a +  \frac{1}{a}  \bigg)^{2} = 13 \\  \\  \bigg(a +  \frac{1}{a}  \bigg) =  \pm \sqrt{13}

5 0
3 years ago
Mell is twice as old as Jerry. If 16 is subtracted from Mell’s age and 16 is added to Jerry’s age, their ages will be equal. Wha
irga5000 [103]

Answer:


Step-by-step explanation:

Let J = Jerry's age

Let M = Mary's age = 2J

 

M - 16 = J + 16

 

Substitute 2J for Mary's age

 

2J - 16 = J + 16

2J - J - 16 = 16

J = 16 + 16

J = 32

 

Jerry is 32.

Mary is twice as old as Jerry.

Mary is 2(32) = 64

3 0
3 years ago
Read 2 more answers
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