Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
_____
In the attached graph, the requested line is shown in black.
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452
Answer:
6
Step-by-step explanation:
7900 79 times 100 ------------
4x^2 + 2x = -9
4x^2 + 2x + 9 = 0
remember that the form of quadratic is ax^2 + bx + c = 0
so
a = 4
b = 2
c = 9