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Maslowich
3 years ago
10

On a no wind day, an airplane is flying 2000 miles round trip from Chicago to Boston and back to Chicago with a constant speed o

f 500 mph. About how long would it take to fly the same round trip if there is a wind speed of 100 mph from Chicago to Boston during the whole round trip flight?
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

It would take the plane about 4.17 hours to fly the whole round trip.

Step-by-step explanation:

Assuming that the distance from Chicago to Boston is 2000/2 = 1000 miles.

Since the wind is blowing from Chicago to Boston, when the plane is traveling to Boston, the velocity of the wind adds to the its velocity:

v_1 = 500mph + 100mph = 600mph;

therefore, the time it takes for the plane to go from Chicago to Boston is

t_1 = \dfrac{1000miles}{600mph}

\boxed{ t_1 = 1.67hr}

Now, as the plane flies back from Boston to Chicago, the wind is blowing opposite the direction of its movement; therefore, the wind's velocity subtracts from the velocity of the plane:

v_2 = 500mph-100mph =400mph

and the time taken during the trip is

t_2 = \dfrac{1000miles}{400mph}

\boxed{t_2 = 2.5hr. }

Therefore, the total time taken t_{tot} during the whole round trip is

t_{tot}= t_1+t_2  \\\\t_{tot} = 1.67hr+2.5hr \\

\boxed{t_{tot} = 4.17hr}

Therefore, on the windy day, it would take the plane 4.17 hours to fly the whole round trip

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A rectangle box with a square base and no top needs to be made using 300ft^2 of material. Find the dimensions of the box with th
Yuri [45]

The dimensions of the box are 10 ft and 5 ft

The maximum volume is 500 ft³

Step-by-step explanation:

A rectangle box with

  • A square base and no top
  • It needs to be made using 300 ft² of material
  • It has greatest volume

Surface area of a box without top (SA) = perimeter of base × height + area of the base

Volume of a box (V) = base area × height

Assume that the length of the side of the square base is x and the height of the box is y

∵ It needs to be made using 300 ft² of material

∴ The surface area of the box is 300 ft²

∵ Its base is a square of side length x ft

∴ Perimeter of the base = 4 × x = 4 x

∴ Area of the base = x²

∵ The height of the box = y ft

∵ SA = perimeter of base × height + area of the base

∵ SA = (4x)(y) + x²

∴ SA = 4xy + x²

∵ SA of the box = 300 ft²

- Equate the two expressions of SA

∴ 4xy + x² = 300

Now let us find y in terms of x

- Subtract x² from both sides

∴ 4xy = 300 - x²

- Divide each term by 4x to find y

∴ y=\frac{75}{x}-\frac{1}{4}x

∵ V = area of the base × height

∴ V = x² × y = x²y

- Substitute y by the equation of it above

∴ V=x^{2}(\frac{75}{x}-\frac{1}{4}x)

∴ V=75x-\frac{1}{4}x^{3}

∵ The volume of the box is greatest

- That means differentiate V and equate it by 0

∵ \frac{dV}{dx}=75-\frac{3}{4}x^{2}

∵ \frac{dV}{dx}=0 ⇒ greatest volume

∴ 75-\frac{3}{4}x^{2}=0

- Subtract 75 from both sides

∴ -\frac{3}{4}x^{2}=-75

- Divide both sides by -\frac{3}{4}

∴ x² = 100

- Take √ for both sides

∴ x = 10

Substitute the value of x in the equation of y

∵ y=\frac{75}{10}-\frac{1}{4}(10)

∴ y = 5

The dimensions of the box are 10 ft and 5 ft

∵ V=75x-\frac{1}{4}x^{3}

∵ x = 10

∴ V=75(10)-\frac{1}{4}(10)^{3}

∴ V=750-\frac{1}{4}(1000)

∴ V = 750 - 250

∴ V = 500 ft³

The maximum volume is 500 ft³

Learn more:

You can learn more about the volume in brainly.com/question/6443737

#LearnwithBrainly

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