Answer:
It would take the plane about 4.17 hours to fly the whole round trip.
Step-by-step explanation:
Assuming that the distance from Chicago to Boston is 2000/2 = 1000 miles.
Since the wind is blowing from Chicago to Boston, when the plane is traveling to Boston, the velocity of the wind adds to the its velocity:
;
therefore, the time it takes for the plane to go from Chicago to Boston is
![t_1 = \dfrac{1000miles}{600mph}](https://tex.z-dn.net/?f=t_1%20%3D%20%5Cdfrac%7B1000miles%7D%7B600mph%7D)
![\boxed{ t_1 = 1.67hr}](https://tex.z-dn.net/?f=%5Cboxed%7B%20t_1%20%3D%201.67hr%7D)
Now, as the plane flies back from Boston to Chicago, the wind is blowing opposite the direction of its movement; therefore, the wind's velocity subtracts from the velocity of the plane:
![v_2 = 500mph-100mph =400mph](https://tex.z-dn.net/?f=v_2%20%3D%20500mph-100mph%20%3D400mph)
and the time taken during the trip is
![t_2 = \dfrac{1000miles}{400mph}](https://tex.z-dn.net/?f=t_2%20%3D%20%5Cdfrac%7B1000miles%7D%7B400mph%7D)
![\boxed{t_2 = 2.5hr. }](https://tex.z-dn.net/?f=%5Cboxed%7Bt_2%20%3D%202.5hr.%20%7D)
Therefore, the total time taken
during the whole round trip is
![t_{tot}= t_1+t_2 \\\\t_{tot} = 1.67hr+2.5hr \\](https://tex.z-dn.net/?f=t_%7Btot%7D%3D%20t_1%2Bt_2%20%20%5C%5C%5C%5Ct_%7Btot%7D%20%3D%201.67hr%2B2.5hr%20%5C%5C)
![\boxed{t_{tot} = 4.17hr}](https://tex.z-dn.net/?f=%5Cboxed%7Bt_%7Btot%7D%20%3D%204.17hr%7D)
Therefore, on the windy day, it would take the plane 4.17 hours to fly the whole round trip