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Naddik [55]
2 years ago
8

You randomly draw twice from this deck of cards

Mathematics
1 answer:
Serggg [28]2 years ago
3 0

The probability of not drawing C in neither draw is P = 0.5

<h3>How to get the probability?</h3>

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

P = p*q = (3/4)*(2/3) = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

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Find the value of x, y, and z in the rhombus below.
Yuki888 [10]

Solution:

<u>It should be noted:</u>

  • Opposite sides of a rhombus are always equal.
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<u>Thus:</u>

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<u>Finding x:</u>

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4 0
2 years ago
Read 2 more answers
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belka [17]

Answer:

Option B is correct

Step-by-step explanation:

Hope that helped u

6 0
3 years ago
Select the correct answer.
Vikki [24]

Answer:

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Step-by-step explanation:

S₃₀ = 30/2 [ 2 x 6 + (30 - 1) x 7 ]

15 [ 12 + 29 x 7 ]

15 [ 12 + 203 ]

15 x 215

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3 0
3 years ago
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