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2 years ago

You randomly draw twice from this deck of cards

Mathematics

1 answer:

Serggg [28]2 years ago

3 0

The probability of not drawing C in neither draw is P = 0.5

<h3>How to get the probability?</h3>

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

P = p*q = (3/4)*(2/3) = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

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Answer:

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Step-by-step explanation:

As we can see in the figure that point T is the mid point of rectangle and there are two diagonals QS and PR

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From equation (i)

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Putting this value in equation (ii)

y + 3 = 2( $\frac{2y}{3}$ )

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Step-by-step explanation:

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