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Lynna [10]
3 years ago
16

Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain

is all real numbers. The range is y > 3. The initial value is 3. The initial value is 9. The simplified base is .
Mathematics
2 answers:
fiasKO [112]3 years ago
9 0

Answer:

ACE

Step-by-step explanation:

Studentka2010 [4]3 years ago
4 0

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is 9\sqrt{2}

Step-by-step explanation:

The given function is f(x)=3(\sqrt{18})^x.

To find the initial value, we put x=0 into the function:  

f(0)=3(\sqrt{18})^0.

f(0)=3(1)=3.

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is y\:>\:0

The simplified base is 3\sqrt{18}=3\sqrt{9\times2}.

3\sqrt{18}=3\sqrt{9}\times\sqrt{2}

3\sqrt{18}=3\times3\times\sqrt{2}

3\sqrt{18}=9\sqrt{2}

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Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line −2x+3y=12?
givi [52]

We are given first equation: −2x+3y=12.

Converting it in slope-intercept form

3y=2x + 12

y= 2/3 x + 12/3

y= 2/3 x + 4.

<em>Slope of the given equation is 2/3.</em>


<em>Note: When slopes are same, lines would be parallel.</em>

<em>When slope are negative reciprocals, lines would be perpendicular.</em>

<em>When neither same nor negative reciprocal, the lines neither parallel nor perpendicular.</em>


1) First option : -2x+y=12.

In slope-intercept form y = 2x +12.

Slope is 2 there.

<h3>Neither parallel nor perpendicular to the line −2x+3y=12.</h3>

2) 3x+2y=-2

In slope-intercept form y = -3/2 x - 1.

Slope = -3/2.

Slope are negative reciprocal to slope of −2x+3y=12 equation.

<h3>Therefore, lines are perpendicular.</h3>

3) y=2/3x-1

Slope = 2/3.

<h3>Slopes are same therefore lines are parallel.</h3>

4) -2x+3y=11

y = 2/3 x + 11/3.

<h3>Slopes are same therefore lines are parallel.</h3>
4 0
4 years ago
Anyone have any tricks to make quadratic functions less-intimidating? I’m a bit confused with all the numbers and rules.
DerKrebs [107]
Try to find ways that you can easily remember formulas. For example, when you find the line of symmetry the equation is y=-b/2a. A way you can remember that is by saying negative tuba. It seems silly but it’s something you can do for most equations so it doesn’t seem so intimidating.
5 0
3 years ago
The cost of admission to the state fair changed from 8.50 last year to 10.00 this year.round to the nearest tenth show your work
Nitella [24]

Answer:

A. What is the percent of change from last year to this year.

Answer: The percent of change from last year to this year is:

\frac{10.00 - 8.50}{8.50} \times 100

\frac{1.50}{8.50} \times 100

17.65 \%

Therefore, the percent change from last year to this year is 17.65%

B. Is this a percent increase or decrease?

Answer: This is a percent increase.

C. If you have 25% off coupon to use on 10.00 ticket what is the cost?

Answer: The 25% of 10.00 is given below:

\frac{25}{100} \times 10.00

0.25 \times 10.00

2.5

Therefore, the cost is:

10.00 -2.5 =7.5



4 0
3 years ago
Is LNM OQP? If so, name the postulate that applies.
son4ous [18]
Answer: Choice B) Congruent - SAS

--------------------------------------------------------------

SAS stands for "Side Angle Side"

LM = OP is given. This is represents the first "S" in "SAS"
angle M = angle P is given. This is the "A" in "SAS"
MN = PQ is given. This is the second "S" in "SAS"

Note how the angles are between the given sides. 
8 0
3 years ago
(1 point) The intensity of light at a depth of x meters below the surface of a lake satisfies the differential equation dIdx=(−1
snow_tiger [21]

Answer:

0.573 m

Step-by-step explanation:

a. To find the depth, x, we first solve the differential equation to find the expression for I  

dI/dx = (-1.21)I

dI = (-1.21)Idx

dI/I = -1.21dx

Integrating both sides, we have

∫dI/I = ∫-1.21dx

㏑I = -1.21x + C

I = exp(-1.21x + C)

I = exp(-1.21x)exp(C) Let exp(C) = A

I =Aexp(-1.21x)

when x = 0, I = L. Substituting these into the equation, we have

L = Aexp(-1.21 × 0)

L = Aexp(0)

L = A

So, I = Lexp(-1.21x)

we want to find x when I = L/2.

So, L/2 = Lexp(-1.21x)

1/2 = exp(-1.21x)

-1.21x= ㏑(1/2)

-1.21x= -㏑2

x = -㏑2/-1.21

x =  0.693/1.21

x = 0.573 m

6 0
3 years ago
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