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Lynna [10]
3 years ago
16

Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain

is all real numbers. The range is y > 3. The initial value is 3. The initial value is 9. The simplified base is .
Mathematics
2 answers:
fiasKO [112]3 years ago
9 0

Answer:

ACE

Step-by-step explanation:

Studentka2010 [4]3 years ago
4 0

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is 9\sqrt{2}

Step-by-step explanation:

The given function is f(x)=3(\sqrt{18})^x.

To find the initial value, we put x=0 into the function:  

f(0)=3(\sqrt{18})^0.

f(0)=3(1)=3.

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is y\:>\:0

The simplified base is 3\sqrt{18}=3\sqrt{9\times2}.

3\sqrt{18}=3\sqrt{9}\times\sqrt{2}

3\sqrt{18}=3\times3\times\sqrt{2}

3\sqrt{18}=9\sqrt{2}

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Howdy!
posledela

Answer:

A) Central angle has same measure as intercepted arc.

  • mCE = mCD + mDE = 20° + 90° = 110°

B) Opposite angles of cyclic quadrilateral are supplementary.

  • mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
  • m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
  • m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
  • mQP = 360° - (90° + 76° + 72°) = 122°

C)

  • m∠MLN = m∠MRN as same arc MN is intercepted
  • m∠LMN is right angle as opposite side is diameter.
  • ∠MNL is complementary with ∠MLN which is same as ∠MRN
  • m∠MNL = 90° - 47° = 43°

D) Tangent secant angle is half of the intercepted arc.

<em>It seems wrong. Should be mQP instead of mQR</em>

  • mQP = 2*m∠RQP = 2*74° = 148°
8 0
3 years ago
I need help with algebra
aalyn [17]
To find the equation of a line using two coordinate points, use the slope intercept formula, (y2-y1)/(x2-x1). Using this formula, plug in your values from the two coordinates (-5, -5) and (1, -3). This would look like this:
(-3-(-5))/(1-(-5))
When simplified, you should get 2/6 or 1/3 as your slope or m value. Now that you have your slope, now use your slope intercept equation y=mx+b and plug in your known values. Since you know the m value is 1/3 and you can use one of your set of points to plug into the x and y values, you can plug in these values and solve for b (the coordinate you use doesn't matter but I'm just using the (1,-3)). This would look like this:
-3=1/3(1)+b

When you simplify, you should get -3=1/3+b and when you subtract both sides by 1/3, you should get b=-10/3.

Now that you have your m and b values, you can conclude that your equation for the line would be y=1/3x-10/3



7 0
4 years ago
Garrison Company uses the retail method of inventory costing. It started the year with an inventory that had a retail cost of $4
ycow [4]

Answer:1.08

Step-by-step explanation:just multiply it together

7 0
3 years ago
Read 2 more answers
Is this statement true or false? The perimeter of an equilateral figure can be found by multiplying the number of sides by the l
photoshop1234 [79]

Answer:

true

Step-by-step explanation:

5 0
3 years ago
Simplify the following equation completely. Write your answer in only positive exponents.
kotegsom [21]

Answer:

Appears to be A with a typo.

Should be \frac{3a^{12}*b^{3}}{4}

Step-by-step explanation:

To evaluate or simplify expressions with exponents, we use exponent rules.  

1. An exponent is only a short cut for multiplication. It simplifies how we write the expression.

2. When we multiply terms with the same bases, we add exponents.

3. When we divide terms with the same bases, we subtract exponents.

4. When we have a base to the exponent of 0, it is 1.

5. A negative exponent creates a fraction.

6. When we raise an exponent to an exponent, we multiply exponents.

7. When we have exponents with parenthesis, we apply it to everything in the parenthesis.

We will use these rules to simplify.

\frac{12a^8b^{-7}}{(4a^{-2}b^{-5})^2}\\\\\frac{12a^8b^{-7}}{4^2a^{-4}b^{-10}} \\\\\frac{12}{16}*\frac{a^8}{a^{-4}}*\frac{b^{-7}}{b^{-10}}\\\\\frac{3}{4}*a^{8--4}*b^{-7--10}\\\\    \frac{3}{4}*a^{12}*b^{3}

7 0
3 years ago
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