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Lyrx [107]
3 years ago
14

Answer?? what is the slope

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

<h3>home / algebra / linear equations / slope </h3><h3>Slope </h3><h3>Slope is a value that describes the steepness and direction of a line. In variable format, it is commonly represented by the letter m. The slope of a line is also called its gradient or rate of change. </h3><h3> </h3><h3>The slope formula is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x1, y1) and (x2, y2), to calculate the change in y over the change in x. </h3><h3> </h3><h3>Slope is a ratio that includes how y changes for every unit increase of x: </h3><h3> </h3><h3> </h3><h3> </h3><h3>A graphical depiction is shown below. </h3><h3> </h3><h3>home / algebra / linear equations / slope </h3><h3>Slope </h3><h3>Slope is a value that describes the steepness and direction of a line. In variable format, it is commonly represented by the letter m. The slope of a line is also called its gradient or rate of change. </h3><h3> </h3><h3>The slope formula is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x1, y1) and (x2, y2), to calculate the change in y over the change in x. </h3><h3> </h3><h3>Slope is a ratio that includes how y changes for every unit increase of x: </h3><h3> </h3><h3> </h3><h3> </h3><h3>A graphical depiction is shown below. </h3><h3> </h3><h3> </h3><h3>Below is an example of using the slope formula. </h3><h3> </h3><h3>Example </h3><h3> </h3><h3>Given the following points: </h3><h3> </h3><h3>(-2, 3) and (4, 1) </h3><h3> </h3><h3> </h3><h3> </h3><h3>As the magnitude of the slope increases, the line becomes steeper. As the magnitude of the slope decreases, the opposite occurs, and the line becomes less steep. </h3><h3> </h3><h3>For linear equations in slope-intercept form, y = mx + b, m indicates the slope of the line. </h3><h3> </h3><h3>Slope also indicates the direction of a line. A line with a positive slope, said to be increasing, runs upwards from left to right. </h3><h3> </h3><h3>A line with a negative slope, said to be decreasing, runs downwards from left to right. </h3><h3> </h3><h3>Example </h3><h3> </h3><h3>Positive slope Negative slope </h3><h3>  </h3><h3> </h3><h3> </h3><h3>A horizontal line has a slope of zero because y does not change. A vertical line has an undefined slope because you cannot divide by zero (x does not change). </h3><h3> </h3><h3>Example </h3><h3> </h3><h3>Zero slope Undefined slope </h3><h3>y = 2 x = -3 </h3><h3> </h3><h3> </h3><h3>Parallel lines have the same slope. </h3><h3> </h3><h3>Example </h3><h3> </h3><h3>y = 2x + 3 and y = 2x - 4 both have a slope of 2, so they are parallel, as shown below: </h3><h3> </h3><h3> </h3><h3>Perpendicular lines have slopes that are "opposite reciprocals" of each other. In this context, "opposite" refers to the change in sign from + to - or vice versa. "Reciprocal" refers to flipping the numerator and denominator of the value. For example, the reciprocal of x is . </h3><h3> </h3><h3>Therefore, taking the opposite reciprocal of something means that you flip the sign and the numerator and denominator. </h3><h3> </h3><h3>Example </h3><h3> </h3><h3>-3x - 2 has a slope of -3, and y = ⅓x + 1 has a slope of ⅓. -3 and ⅓ are opposite reciprocals, so the equations are perpendicular: </h3><h3> </h3><h3 />

Step-by-step explanation:

<h3>#hopeithelps</h3><h3>stay safe and keep well</h3><h3 /><h3>can you mark me as brainliest pls</h3>

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sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
3 years ago
Boris buys the newspaper every morning.
Lelu [443]

Answer:

11.5

Step-by-step explanation:

1.50 x 5 = 7.50

0.74 + 3.25 = 4

7.50 + 4 = 11.5

3 0
3 years ago
Utilize graphing to find the solution to
Llana [10]

Answer:

(4, -3)

Step-by-step explanation:

To solve this with graphing all you need to do is enter both equations in a graphing calculator (you can use desmos online) and then find the point where both lines intersect.

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