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Eduardwww [97]
3 years ago
12

Based on your observations in question 7, what general conclusion can you draw about any line that is parallel to one side of a

triangle and intersects the other two sides?
(question 7. Now check the boxes for Show Segment Parallel to AC and Show Segment Parallel to AB. Find the ratio of BF to FC and the ratio of GB to AG. Then find the ratio of IC to BI and the ratio of HC to AH. (If you want to move , select point F, and if you want to move , select point H.) What can you say about the relationship between the pairs of lengths in each case? (The ratio of BF to FC is proportional to the ratio of GB to AG. Similarly, the ratio of IC to BI is proportional to the ratio of HC to AH.))
Mathematics
1 answer:
oee [108]3 years ago
5 0

Answer: A line parallel to one side of a triangle and intersects the other two sides divides the two sides of the triangle proportionally.

Got this straight from Edmentum

Step-by-step explanation:

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Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
Which situation(s) could by modeled by a linear function?
liraira [26]
1 and 111 only would be your answer
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When these data are graphed on a coordinate grid, the points all lie on the same line. What are the slope and y-intercept of thi
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Answer:

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Which of the following is the number if sides a polygon can have to form a regular tessallation?
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None of the options is true.

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<h3>What is the polygon?</h3>

A polygon is said to be regular if all interior angles and all sides are equal.

The regular polygon of side 3, when joined together can be named: 3.3.3.

The regular polygon of side 4, when joined together can be named 4.4.4.

The regular polygon of side 6, when joined together can be named 6.6.6.

So, a regular tessellation is formed, from a regular polygon having,3,4, and 6 Sides.

None of the sides of the polygon, which is given in the option, can be used to form a regular tessellation.

None of the options is true.

To learn more about the polygon visit:

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Help it is Parts of an Algebraic Expression
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Answer:

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