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3 years ago

The real numbers whose decimals do not end and do not repeat are (irrational numbers / rational numbers).

Mathematics

2 answers:

Zigmanuir [339]3 years ago

6 0

Answer:

Irrational numbers

Step-by-step explanation:

Rational numbers are integers. They don't have repeating decimals.

An irrational number is not an integer, because irrational number are "not rational" and all integers can be represented as rational, so irrational numbers decimals repeat.

pantera1 [17]3 years ago

3 0

9514 1404 393

Answer:

irrational numbers

Step-by-step explanation:

The real numbers whose decimals do not end and do not repeat are irrational numbers.

If a decimal number ends or repeats, it can be represented by the ratio of two integers. That is the essence of a rational number.

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If anyone can help, thanks!

saul85 [17]

Note: This is a perfect application for equations of ratios.

50 40

------- = ------- and so 50x = 1200, or 5x = 120, or x = 24 (miles).

30 x

3 0

4 years ago

Integers from 1 to 50

aivan3 [116]

...every number between 1 and 50 is an integer

6 0

3 years ago

Urgent please help..

Katyanochek1 [597]

Answer:

18π

Step-by-step explanation:

Lateral Surface Area = 2πrh

Plug in the numbers into the equation.

but leave the pi

6 0

3 years ago

Whats the distance between (-8,-7) (8,-4)

balandron [24]

To find the distance between points, use the distance formula.

Distance formula: $\sqrt{ (x_{2} - x_{1})^{2} + ( y_{2} - y_{1})^{2} }$

Plug in your values for $x_{2}, x_{1}, y_{2}, y_{1}$ using (-8, -7) and (8, -4) and solve.

$\sqrt{(8 - (-8))^{2}+(-4 - (-7))^{2}}$
$\sqrt{(8+8)^{2}+(-4+7)^{2}}$
$\sqrt{(16)^{2}+(3)^{2}}$
$\sqrt{256+9}$
$\sqrt{265}$ ≈ $16.28$

Answer:
Approximately 16.28 units.

8 0

3 years ago

Gm how are yall doing? can yall plz help me with this and not just take my points

timama [110]

Answer:

m+J=G

Step-by-step explanation:

All you need to do is get G by itself by adding J to both sides. Now the equation will read m+J=G and you just solved for G.

5 0

3 years ago

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