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natita [175]
3 years ago
10

I have 12 oranges and 4 bananas I need help finding the ratio of them

Mathematics
1 answer:
ddd [48]3 years ago
3 0

We can simplify the ratio 12 : 4 by dividing both terms by the greatest common factor (GCF).

The GCF of 12 and 4 is 4.

Divide both terms by 4.
12 ÷ 4 = 3
4 ÷ 4 = 1

Therefore:
12 : 4 = 3 : 1
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6f+f(f+2)+3 f*to the 2nd power-4f​
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Answer:

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A square based prism and a cylinder both have
Anna11 [10]

Answer:

Parameter of base = 70.88 inch (Approx.)

Step-by-step explanation:

Given:

Volume of cylinder = 3768 cubic inch

Height of Prism = 12 inch

Find;

Parameter of base

Computation:

Volume of cylinder = Volume of Prism

3768 = (L)(B)(H)

3768 = (L)(B)(12)

(L)(B) = 314

L = B

So.

L = 17.72 inch

B = 17.72 inch

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8 0
2 years ago
Please help solve the inequality.
gulaghasi [49]

Answer:

Are there two you're asking for?

#2: x ≥ 9

#3: x > -2

Step-by-step explanation:

#2 Work:

x - 13 ≥ -4

Step 1: Add 13 to both sides

x - 13 + 13 ≥ -4 + 13

Add -4 and 13 to get 9.

x ≥ 9

#3 Work:

x/2 > -1

Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same

x/2 * 2 > -1 * 2

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5 0
2 years ago
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DochEvi [55]
In order from left to right its RRRT
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3 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (4, 4)(4,4) and (10, 7) ?(10,7)? Write your answer in simplest form
Mashutka [201]

The slope of line passing through the points (4, 4) and (10, 7) is \frac{1}{2}

<em><u>Solution:</u></em>

Given that, we have to find the slope of line that passes through the points (4, 4) and (10, 7)

The slope of line passing through (x_1 , y_1) and (x_2, y_2) is given as:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Given two points are (4, 4) and (10, 7)

\text{ Here } x_1 = 4 ; y_1 = 4; x_2 = 10; y_2 = 7

Substituting the values in formula, we get

\begin{aligned}&m=\frac{7-4}{10-4}\\\\&m=\frac{3}{6}\end{aligned}

Reducing to lowest terms, we get

m=\frac{1}{2}

Thus slope of line passing through given points is \frac{1}{2}

8 0
3 years ago
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