The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
Answer:
(1, 2 )
Step-by-step explanation:
Given the 2 equations
3x + y = 5 → (1)
5x - 4y = - 3 → (2)
Rearrange (1) expressing y in terms of x by subtracting 3x from both sides
y = 5 - 3x → (3)
Substitute y = 5 - 3x into (2)
5x - 4(5 - 3x) = - 3 ← distribute and simplify left side
5x - 20 + 12x = - 3
17x - 20 = - 3 ( add 20 to both sides )
17x = 17 ( divide both sides by 17 )
x = 1
Substitute x = 1 into (3) for corresponding value of y
y = 5 - 3(1) = 5 - 3 = 2
Solution is (1, 2 )
Answer:
1 and -8
Step-by-step explanation:
![1 + (-8) = 1 - 8 = -7](https://tex.z-dn.net/?f=1%20%2B%20%28-8%29%20%3D%201%20-%208%20%3D%20-7)
Answer:
Step-by-step explanation:
(cos7A + cos3A - cos5A - cosA)÷(sin7A - sin3A - sin5a + sinA)
By using transformations,
[(cos7A - cos5A) + (cos3A - cosA)]÷[(sin7A - sin5A) - (sin3A - sinA)]....
we get...
=[(2sin6A.sinA)+(2sin2A.sinA)]÷[(2cos6A.sinA)-(2cos2A.sinA)]...
=[{2sinA(sin6A+sin2A)}]÷[{2sinA(cos6A-cos2A)]
=[{2sin4A.cos2A}÷{2sin4A.sin2A}]
=[(cos2A)÷(sin2A)]
=cot2A
Okay, to work out the original price, all you have to do is get the sale price ($146.54) and then divide it by 1 - 0.[whatever the percentage is]. In this case, the percentage is 15%, so you do 1 - 0.15 = 0.85.
So to work out the original price, you do:
146.54 ÷ 0.85 = $172.40
The original price is $172.40. :)