Let x be the original radius. Given that a semicircle will have an arc length of half of a circumference and C=2pr, the arc length will be just pr.
Now the difference of arc is then going to be:
p(6+x)-px
p(6+x-x)
6p inches
So the arc will be 6p inches longer. Or if you wish to approximate...
≈18.85 inches
Ln20+ln5=2ln x
ln(20*5) = ln x^2
ln 100 = ln x^2
100 = x^2
x = 10 second option
Answer:
Step-by-step explanation:
(find common denominator)
(reduce to simplest form)
Hope this helps :)
Answer:
y = x - 2
Step-by-step explanation:
slope intercept form
y = mx + b
m = rise / run = -5 / 6
b = -2
y = x - 2
Answer: (11/2)π units.
Step-by-step explanation:
I've attached the solution.
Before seeing it there is a theorem you should remember.
The angle subtended by an arc of a circle at its center is twice of the angle it subtends anywhere on the circle’s circumference.